求JAVA的两整数输出最大最小值以及两个数的和差积商的程序

Question

急急急！！！！跪求高手给答案．．．感激不尽．．．

Answer 1

/**
* @(#)Zhidao1.java
*
*
* @author 智鸱儿—zhichier
* @version 1.00 己丑年二月廿六日-2009/3/22
*/

public class Zhidao1 {

private int x;
private int y;

//构造方法一—默认构造方法
public Zhidao1() {
x = 1;
y = 1;
}

//构造方法二—带参数的构造方法
public Zhidao1(int x, int y) {
this.x = x;
this.y = y;
}

//求和函数
public int qiuHe() {
return x + y;
}

//求差函数
public int qiuCha() {
return x - y;
}

//求积函数
public int qiuJi() {
return x * y;
}

//求商函数
public double qiuShang() {
return y == 0 ? 0.0 : ((double)x / (double)y);
}

//求余函数
public int qiuYu() {
return y == 0 ? 0 : x % y;
}

//求最大值函数
public int qiuZuida() {
return x > y ? x : y;
}

//求最小值函数
public int qiuZuixiao() {
return x < y ? x : y;
}

public static void main(String args[]) {

//用默认构造方法，x和y被分别设置为1
Zhidao1 zd1= new Zhidao1();

System.out.println("x和y的和是：" + zd1.qiuHe());
System.out.println("x和y的差是：" + zd1.qiuCha());
System.out.println("x和y的积是：" + zd1.qiuJi());
System.out.println("x和y的商是：" + zd1.qiuShang());
System.out.println("x和y的余是：" + zd1.qiuYu());
System.out.println("x和y的最大值是：" + zd1.qiuZuida());
System.out.println("x和y的最小值是：" + zd1.qiuZuixiao());

//用带参数构造方法，x和y被分别设置为3和5
Zhidao1 zd2 = new Zhidao1(3, 5);

System.out.println("x和y的和是：" + zd2.qiuHe());
System.out.println("x和y的差是：" + zd2.qiuCha());
System.out.println("x和y的积是：" + zd2.qiuJi());
System.out.println("x和y的商是：" + zd2.qiuShang());
System.out.println("x和y的余是：" + zd2.qiuYu());
System.out.println("x和y的最大值是：" + zd2.qiuZuida());
System.out.println("x和y的最小值是：" + zd2.qiuZuixiao());
}

}

Answer 2

import java.io.*;

class SEV {
public static void main(String[] args) throws IOException{
int max,min;
double sh;
InputStreamReader reader = new InputStreamReader(System.in);
BufferedReader input = new BufferedReader(reader);
System.out.print("please input m:");
String r = input.readLine();
int m = Integer.parseInt(r);
System.out.print("please input n:");
String s = input.readLine();
int n = Integer.parseInt(s);
if(m>n) {max=m;min=n;}
else {min=m;max=n;}
sh=(double)max/min;
System.out.println("max="+max);
System.out.println("min="+min);
System.out.println("max+min="+(max+min));
System.out.println("max-min="+(max-min));
System.out.println("max*min="+(max*min));
System.out.println("max/min="+sh);
}
}

Answer 3

以前也有过类似的经历

Answer 4

这。。。太简单了 作业题吧

Answer 5

HOHO~我的简单！

public class C {

public static void main(String[] args) {
int a,b;
System.out.println("请依次输入2个整数！");
Scanner scan1=new Scanner(System.in);
int i=scan1.nextInt();
Scanner scan2=new Scanner(System.in);
int j=scan2.nextInt();
a=i>j?i:j;
b=i<j?i:j;
System.out.println("最大数为:"+a);
System.out.println("最小数为:"+b);
double c=(double)i/(double)j;
System.out.println("和："+(i+j)+"商："+c+"积："+(i*j)+"差："+(i-j));
}

}