同理得:
y=(根号3-1)^2/(根号3-1)(根号+1)=(3+1-2根号3)/(3-1)=2-根号3
X^2-Y^2=(3+2根号2)^2-(2-根号3)^2
=9+12根号2+8-(4+3-4根号3)
=10+12根号2+4根号3追答
x=(根号2+1）/(根号2-1）=（根号2+1）^2/【(根号2-1）（根号2+1）】=（2+1+2根号2）/(2-1)=3+2根号2
同理得:
y=(根号3-1)^2/(根号3-1)(根号+1)=(3+1-2根号3)/(3-1)=2-根号3
X^2-Y^2=(3+2根号2)^2-(2-根号3)^2
=9+12根号2+8-(4+3-4根号3)
=10+12根号2+4根号3
已知X=根号2-1分之根号2+1,Y=根号3+1分之根号3-1,求X的平方-Y的平方
x=(根号2+1）\/(根号2-1）=（根号2+1）^2\/【(根号2-1）（根号2+1）】=（2+1+2根号2）\/(2-1)=3+2根号2 同理得:y=(根号3-1)^2\/(根号3-1)(根号+1)=(3+1-2根号3)\/(3-1)=2-根号3 X^2-Y^2=(3+2根号2)^2-(2-根号3)^2 =9+12根号2+8-(4+3-4根号3)=10+...
已知X=根号2-1分之根号2+1,Y=根号3+1分之根号3-1,求X的平方-Y的平方
x=(根号2+1）\/(根号2-1）=（根号2+1）^2\/【(根号2-1）（根号2+1）】=（2+1+2根号2）\/(2-1)=3+2根号2 同理得:y=(根号3-1)^2\/(根号3-1)(根号+1)=(3+1-2根号3)\/(3-1)=2-根号3 X^2-Y^2=(3+2根号2)^2-(2-根号3)^2 =9+12根号2+8-(4+3-4根号3)=10+...
已知x=根号2-1分之根号2 1y=根号3 1分之根号3-1求x^2-y^2的值
X=(√2+1)\/(√2-1)=(√2+1)^2=3+2√2，Y=(√3-1)\/(√3+1)=(√3-1)^2\/2=2-√3，∴X^2-Y^2 =(3+2√2)^2-(2-√3)^2 =17+12√2-(7-4√3)=10+12√2+4√3。
已知x=根号2加一分之根号2减一,y=根号3减一分之根号3加一,求x平方减y...
已知，x=(√2-1)\/(√2+1)=1-2\/( √2+1)，y=(√3+1)\/(√3-1)=1+2\/(√3-1)，x�0�5-y�0�5=(x-y)(x+y),把x,y代入得：原式=[-2\/ ( √2+1)-2\/ (√3-1)][2+2\/ (√3-1)--2\/ ( √2+1)]解题思路就是这，希望对你...
已知x=根号2 + 1 \/ 根号2 - 1,y=根号3 -1 \/ 根号3+1,求x²-y²的...
x=根号2 + 1 \/ 根号2 - 1=（√2+1）²=3+2√2 y=根号3 -1 \/ 根号3+1=（√3-1）²\/2=2-√3 x²-y²=9+8+12√2-4-3+4√3=10+12√2+4√3 关键是有理化 x²是（根号2 + 1)²\/ （根号2 - 1)²要有整体的思想哦 ...
已知x=根号二+1\/根号二-1 y=根号3-1\/根号三+1求x^2-y^2
解：x=[(根号2)+1]\/[(根号2)--1]=[(根号2)+1]^2\/[(根号2)^2--1^2]=(3+2根号2),y=[(根号3)--1]\/[(根号3)+1]=[(根号3)--1]^2\/[(根号3)^2--1^2]=(4--2根号3)\/2 =2--根号3，所以 x^2=(3+2根号2)^2=9+8+12根号2＝17+12根号2，y^2=(2--根号...
已知x=(根号2+1)\/(根号2-1),y=(根号3-1)\/(根号3+1),求x²-y²的...
x=（根号2+1）\/（根号2-1）=(√2+1)²／(2-1)=2+1+2√2 =3+2√2 y=（根号3-1）\/（根号3+1）=﹙√3-1)²\/(3-1)=(3+1-2√3)\/2 =2-√3 x²-y²=(3+2√2)²-(2-√3﹚²=9+8+12√2-(4+3-4√3)=10+12√2+4√3 ...
...1\/(根号2)+1,y=(根号2)+1\/(根号2)-1,求(x^2-y^2)\/(x^2-y^2)的...
你好！x = (√2 -1)² \/ (√2+1))(√2-1) = (√2 -1)² = 3 - 2√2 y = (√2+1)² \/ (√2-1)(√2+1) = 3+2√2 x+y = 6 x-y = - 4√2 xy = 1 x² - y² = (x+y)(x-y) = 6×(-4√2) = - 24√2 x²+y...
已知X=根号2+1分之根号2-1,Y=根号2-1分之根号2+1,求代数式X^2-XY+...
X=根号2+1分之根号2-1，Y=根号2-1分之根号2+1 X^2=（根号2-1）^2=3-2根号2 XY=1 Y^2=（根号2+1）^2=3+2根号2 X^2-XY＋ Y^2=3-2根号2-1+3+2根号2=5
已知x等于根号2-1y等于根号2+1x^2-y平方等于多少
X=根号2+1分之根号2-1,Y=根号2-1分之根号2+1 X^2=（根号2-1）^2=3-2根号2 XY=1 Y^2=（根号2+1）^2=3+2根号2 X^2-XY＋ Y^2=3-2根号2-1+3+2根号2=5
