如何使用sql查出第20-40条纪录

Question

表中仅有一列：name varchar（100）
请问，怎样将20-40条纪录取出来。
mssql2005
哥哥们，都不行啊，选出来的都是错的。

Answer 1

取n到m行

1.
select top m * from tablename where id not in (select top n id from tablename order by id asc/*|desc*/)

2.
select top m * into 临时表(或表变量) from tablename order by columnname -- 将top m笔插入到临时表
set rowcount n --只取n条结果
select * from 表变量 order by columnname desc

3.
select top n * from
(select top m * from tablename order by columnname) a
order by columnname desc

4.如果tablename里没有其他identity列，那么：
先生成一个序列,存储在一临时表中.
select identity(int) id0,* into #temp from tablename

取n到m条的语句为：
select * from #temp where id0 > =n and id0 <= m

如果你在执行select identity(int) id0,* into #temp from tablename这条语句的时候报错,那是因为你的DB中间的select into/bulkcopy属性没有打开要先执行：
exec sp_dboption 你的DB名字,'select into/bulkcopy',true

5.如果表里有identity属性，那么简单：
select * from tablename where identity_col between n and m

6.SQL2005开始.可以使用row_number() over()生成行号
;with cte as
(
select id0=row_number() over(order by id),* from tablename
)
select * from cte where id0 between n to m

Answer 2

select * from(select name,row_number() over(order by name) as rowNum from 表名 order by name) as t where t.rowNum between 20 and 40

Answer 3

select top 20 name from tablename where name not in (select * top 20 name from tablename )

Answer 4

select top 40 name from tab except select top 20 name from tab

Answer 5

mysql or mssql?