C#中单击按钮打开选择文件对话框

Question

我在窗体中创建了一个“选择文件”按钮，想单击这个按钮时就能打开一个对话框选择文件，不知该如何设置这个按钮和打开对话框的关系？在线等！多谢
要保存啊

Answer 1

System.Windows.Forms.OpenFileDialog openFileDialog1 = new System.Windows.Forms.OpenFileDialog();
System.Windows.Forms.ImageList imageList1 = new System.Windows.Forms.ImageList();
System.Collections.ArrayList imgList = new System.Collections.ArrayList();

protected void button1_Click(object sender, EventArgs e)
{
this.openFileDialog1.Filter = "jpg文件(*.jpg)|*.jpg|gif文件(*.gif)|*.gif";

if (this.openFileDialog1.ShowDialog() == DialogResult.OK)
{
string PicFileName = this.openFileDialog1.FileName;
this.imgList.Add(PicFileName);
this.imageList1.Images.Add(Image.FromFile(PicFileName));
}
}

Answer 2

protected void button1_Click(object sender, EventArgs e)
{
this.openFileDialog1.Filter = "*.*";

if (this.openFileDialog1.ShowDialog() == DialogResult.OK)
{
string FileName = this.openFileDialog1.FileName;
// 你的 处理文件路径代码
}

}

Answer 3

需要保存吗？