C语言编写小程序

Question

输入5个学生4门课程的成绩，之后计算：
1，每个学生的总分，
2，每门课程的平均分，
3，输出总分最高的学生的姓名和总成绩。
每项都不能少，高分啊！
要有注解，急，急，急！

Answer 1

先给你看运行结果：
Please Input Student No.1's Name,Score1,Score2,Score3,Score4:
Miles 90 98 78 67
Please Input Student No.2's Name,Score1,Score2,Score3,Score4:
Kelly 89 77 77 66
Please Input Student No.3's Name,Score1,Score2,Score3,Score4:
Token 78 67 23 90
Please Input Student No.4's Name,Score1,Score2,Score3,Score4:
Uole 78 56 32 99
Please Input Student No.5's Name,Score1,Score2,Score3,Score4:
Tek 34 78 98 67

Name SumScore
Miles 333
Kelly 309
Token 258
Uole 265
Tek 277

Course AverageScore
1 73.80
2 75.20
3 61.60
4 77.80

Best Student
Miles 333
Press any key to continue

代码:

#include <stdio.h>

struct Student
{
int iScore[4];
char szName[32];
int iSumScore;
};

void main()
{
int i,iCourse,BestID;
int SumCourse[4]={0};//每门课的总分
struct Student stu[5]={0}; //5名学生
for (i=0;i<5;i++)
{
printf("Please Input Student No.%d's Name,Score1,Score2,Score3,Score4:\n",i+1);
scanf("%s",stu[i].szName); //读取第i名学生的名字
//读取第i名学生4门课的成绩
for(iCourse=0;iCourse<4;iCourse++)
{
scanf("%d",&stu[i].iScore[iCourse]);
stu[i].iSumScore+=stu[i].iScore[iCourse]; //第i名学生的成绩等于他每门课的成绩之和
SumCourse[iCourse]+=stu[i].iScore[iCourse];//每门课的总分等于每个学生该门课成绩之和
}
}
BestID=0;
//输出每个学生的总分,并找出分数最高的学生
printf("\nName\tSumScore\n");
for (i=0;i<5;i++)
{
printf("%s\t%d\n",stu[i].szName,stu[i].iSumScore);
if (stu[i].iSumScore > stu[BestID].iSumScore)
BestID=i;
}
//输出每门课的平均成绩
printf("\nCourse\tAverageScore\n");
for (iCourse=0;iCourse<4;iCourse++)
{
printf("%d\t%.2f\n",iCourse+1,SumCourse[iCourse]*1.0/5);
}
//输出成绩最好的学生的名称和总分
printf("\nBest Student\n");
printf("%s\t%d\n",stu[BestID].szName,stu[BestID].iSumScore);
}

Answer 2

#include<stdio.h>

int main()
{
float a[5][4],aver[5]={0},sum[5]={0},high=0.0;
char name[5][20];
int i,j,k;
for ( i = 0 ; i < 5 ; i++ )
{
printf("请输入第%d位学生的名字:",i+1);
scanf("%s",name[i]);
printf("请输入第%d位学生的成绩:",i+1);
for ( j = 0 ; j < 4 ; j++ )
{
scanf("%f",&a[i][j]);
sum[i] += a[i][j];
}
if ( sum[i] > high)
{
high = sum[i];
k = i ;
}
}
for ( i = 0 ; i < 4 ; i++ )
{
for ( j =0 ; j < 4 ; j++ )
{
aver[i] += a[j][i];
}
aver[i] /= 4;
}
printf("\n");
for ( i = 0 ; i < 5 ; i++ )
printf("%s的总分是:%.2f\n",name[i],sum[i]);
printf("\n");
for ( i = 0 ; i < 4 ; i++ )
printf("第%d门课的平均分是:%.2f\n",i+1,aver[i]);
printf("\n\n最高分是:%s,他的总分是:%.2f\n",name[k],sum[k]);
printf("\n");
}