批处理如何把两个文件内容合并且不重复

Question

我有2个ini文件 一个是123.ini 另一个是456.ini 两个文件前半部分内容一模一样
123.ini内容为
{
"adf":1200,
"erqwe":1,
"cvzx":10,
"zcasdf":[
{"zxcvadfl<=":10, "tjgfghj":7, "sfgwert":0},
{"adfadsas<=":20, "nmvbnmv":15, "ghjdhd":0}
],
"asdfzxcv":true,
"cvasdfasdf":{
"asdfasdfxzcv":true,
"fgsdfgqawer":10,
"adsfqwer":80,
"dfgdfgsdfg":true,
}
"fbsdfgsadfg":{
"vb":"vb-",
"vb1":"vb1-",
"vb2":"vb2-",
"vb3":"vb3-",
"vb4":"vb4-"
}
}

456的文件内容为：
{
"adf":1200,
"erqwe":1,
"cvzx":10,
"zcasdf":[
{"zxcvadfl<=":10, "tjgfghj":7, "sfgwert":0},
{"adfadsas<=":20, "nmvbnmv":15, "ghjdhd":0}
],
"asdfzxcv":true,
"cvasdfasdf":{
"asdfasdfxzcv":true,
"fgsdfgqawer":10,
"adsfqwer":80,
"dfgdfgsdfg":true,
}
"fbsdfgsadfg":{
"oo":"oo-",
"oo1":"oo1-",
"oo2":"oo2-",
"oo3":"oo3-",
"oo4":"oo4-"
}
}

我想把456.ini合并到123.ini中去实现合并后123.ini的内容为：
{
"adf":1200,
"erqwe":1,
"cvzx":10,
"zcasdf":[
{"zxcvadfl<=":10, "tjgfghj":7, "sfgwert":0},
{"adfadsas<=":20, "nmvbnmv":15, "ghjdhd":0}
],
"asdfzxcv":true,
"cvasdfasdf":{
"asdfasdfxzcv":true,
"fgsdfgqawer":10,
"adsfqwer":80,
"dfgdfgsdfg":true,
}
"fbsdfgsadfg":{
"vb":"vb-",
"vb1":"vb1-",
"vb2":"vb2-",
"vb3":"vb3-",
"vb4":"vb4-",
"oo":"oo-",
"oo1":"oo1-",
"oo2":"oo2-",
"oo3":"oo3-",
"oo4":"oo4-"
}
}

各位大神有什么办法吗

Answer 1

123取最后一个}符前一行之前的部分再接456中"fbsdfgsadfg":{ 行之后的部分组成新文件，按此规则代码如下

@echo off&cd/d "%~dp0"
set "fs="fbsdfgsadfg":{"
set s=%fs:"=\"%
for /f "delims=:" %%i in ('type 123.ini^|findstr/n "}"')do set/a m=%%i-1
for /f "delims=:" %%i in ('type 456.ini^|findstr/nrc:"%s%"')do set/an=%%i
(for /f "tokens=1* delims=:" %%i in ('type 123.ini^|findstr/n .*'
      )do if %%i lss %m% echo;%%j
for /f "skip=%n% tokens=1* delims=:" %%i in (
     'type 456.ini^|findstr/n .*')do echo;%%j
)>789.ini
set/p=处理完毕 正在退出... <nul&ping/n 3 127.1>nul