输出一个二维int型数组中最大的元素、最小元素以及所有元素的平均值（c语言指针实现）

Question

跪求！1

Answer 1

#include <stdio.h>

void main()
{
int i, max, min;
float sum;
int a[3][4] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11};
int *pa = &a[0][0];
max = 0;
min = 0;
sum = 0.0;
for (i = 0; i < sizeof(a) / sizeof(int); i++)
{
if (*pa > max)
{
max = *pa;
}
if (*pa < min)
{
min = *pa;
}
sum += *pa;
pa++;
}
printf("max = %d\nmin = %d\naverage = %.3f\n", max, min, sum / (sizeof(a)/sizeof(int)));
}

Answer 2

#include <stdio.h>
void main()
{
int max, min;
float sum;
int a[3][4] = {0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11};
max = a[0][0];
min = a[0][0];
sum = 0;
for (int i = 0; i < 3; i++)
{
for(int j = 0; j < 4; j++)
{
if(a[i][j] > max)
max = a[i][j];
if(a[i][j] < min)
min = a[i][j];
sum += a[i][j];
}
}
printf("max = %d\nmin = %d\naverage = %.3f\n", max, min, sum/12);
}

Answer 3

排序一下就搞定了啊。