c++程序设计，输入4个整数按从小到大顺序输出

Question

没了，要快啊，我的作业都不会了

Answer 1

#include<iostream.h>

void main()
{
int num[4],i,j,a;
cout<<"请输入四个整数：" ;
for(i=0;i<4;i++){
cin>>num[i];}
cout<<"从小到大排列为：" ;
for(i=0;i<4;i++)
for(j=0;j<i;j++){
if (num[j]>num[j+1])
{a=num[j];
num[j]=num[j+1];
num[j+1]=a;
}
}
for(i=0;i<4;i++)
cout<<num[i]<<" ";
cout<<endl;
}

Answer 2

我在VC上编译可以运行
#include "stdafx.h"
#include "iostream"
using namespace std;

int main(int argc, char* argv[])
{
int a[4];
int b,i;
cout << "输入整数\n";
for( i=0;i<4;i++)
{
cout<<"输入第" << i+1 <<"个整数\n";
cin >> a[i];
}
for(int j=3;j>0;j--)
{
for( i=0;i<j;i++)
{
if (a[i] > a[i+1])
{
b = a[i];
a[i] = a[i+1];
a[i+1] = b;
}
}
}
cout<<"最后结果为\n";
for( i=0;i<4;i++)
cout <<a[i]<<endl;
return 0;
}

Answer 3

#include<iostream>
#include
<algorithm>
using
namespace
std;
int
main()
{
int
num[4];
cin>>num[0]>>num[1]>>num[2]>>num[3];
sort(&num[0],
&num[0]+4);
cout<<num[0]<<"
"<<num[1]<<"
"<<num[2]<<"
"<<num[3];
return
0;
}

Answer 4

#include<iostream>
#include
<algorithm>
using
namespace
std;
int
main()
{
int
num[4];
cin>>num[0]>>num[1]>>num[2]>>num[3];
sort(&num[0],
&num[0]+4);
cout<<num[0]<<"
"<<num[1]<<"
"<<num[2]<<"
"<<num[3];
return
0;
}

Answer 5

#include<iostream>
#include <algorithm>
using namespace std;

int main()
{
int num[4];
cin>>num[0]>>num[1]>>num[2]>>num[3];
sort(&num[0], &num[0]+4);
cout<<num[0]<<" "<<num[1]<<" "<<num[2]<<" "<<num[3];
return 0;
}