滴定混合碱时,若v1<v2时,试样的组成如何

Answer 1

你没有给出完整的题目，所以不好下结论。双指示剂法滴定混合碱时，一般V1是指酚酞褪色时的盐酸消耗体积，V2是指继续滴定时另外消耗的盐酸体积，按这种默认的体积分段计算方法，答案应该是Na2CO3，如果是NaOH，应该是V1>0, V2=0；但有时出题时，如果表述为取两份等量的混合碱，一份以酚酞指示，盐酸滴定体积为V1，另一份以甲基橙指示，滴定体积为V2。V1=V2，显然，这种表述的结果应该是NaOH。（我出分析试题时有时也会设这样的陷阱）如果题目不是第二种表述（或相似表述），则答案就是错的，你的判断正确！

Answer 2

答案应该是Na2CO3，如果是NaOH，应该是V1>0, V2=0；但有时出题时，如果表述为取两份等量的混合碱，一份以酚酞指示，盐酸滴定体...

Answer 3

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