1． 编程实现：输入一个整数，判定它能否为3、5、7整除，并输出下列信息之一：1）

Question

这道题是我毕业卷子上的，能否毕业就麻烦各位英雄了

Answer 1

#include <stdio.h>

main ()
{
int a;

scanf ("%d", &a);
if (a % 3 == 0)
printf ("数字%d是3的倍数\n", a);
if (a % 5 == 0)
printf ("数字%d是5的倍数\n", a);
if (a % 7 == 0)
printf ("数字%d是7的倍数\n", a);

}

Answer 2

#include<stdio.h>
int main()
{
int a;
printf("input a number:\n");
scanf("%d",&a);
if(a%3==0) printf("can be divisibilitied by 3\n");
else if(a%5==0) printf("can be divisibilitied by 5\n");
else if(a%7==0) printf("can be divisibilitied by 7\n");
else printf("can be divisibilitied by none of 3,5,7");
return 0;
}

Answer 3

#include <stdio.h>
void main()
{
int number = 0;
printf("please input an integer:");
scanf("%d", &number);
if(number%3 == 0 || number%5 == 0 || number%7 == 0 )
printf("OK");
else
printf("NO");

}

Answer 4

问题不全啊