为啥错误 error C2181: illegal else without matching if

Question

#include<stdio.h>
#include<math.h>
int main()
{double x,y,p1,p2,p3,p4,p5,p6;
printf("请输入奖金x:");
scanf("%f",&x);
if (x<=100000)
p1=0.1;
#include<stdio.h>
#include<math.h>
int main()
{double x,y,p1,p2,p3,p4,p5,p6;
printf("请输入奖金x:");
scanf("%f",&x);
if (x<=100000)
p1=0.1;
y=x*p1;
else if (x<=200000)
p2=0.075;
y=100000*p1+(x-100000)*p2;
else if (x<=400000)
p3=0.05;
y=100000*p1+100000*p2+(x-200000)*p3;
else if (x<=600000)
p4=0.03;
y=100000*p1+100000*p2+200000*p3+(x-400000)*p4;
else if (x<=1000000)
p5=0.015;
y=100000*p1+100000*p2+200000*p3+200000*p4+(x-600000)*p5;
else
p6=0.01;
y=100000*p1+100000*p2+200000*p3+200000*p4+400000*p5+(x-1000000)*p6;
printf("奖金总数为:10.2f%.\n",y);
return 0;
}

Answer 1

#include<stdio.h>
#include<math.h>
int main()
{
    double x,y,p1,p2,p3,p4,p5,p6;
    printf("请输入奖金x:");
    scanf("%f",x);
    if (x<=100000)
    {
        p1=0.1;
        y=x*p1;
    }
    else if (x<=200000)
    {
        p2=0.075;
        y=100000*p1+(x-100000)*p2;
    }
    else if (x<=400000)
    {
    p3=0.05;
    y=100000*p1+100000*p2+(x-200000)*p3;
    }
    else if (x<=600000)
    {
    p4=0.03;
    y=100000*p1+100000*p2+200000*p3+(x-400000)*p4;
    }
    else if (x<=1000000)
    {
    p5=0.015;
    y=100000*p1+100000*p2+200000*p3+200000*p4+(x-600000)*p5;
    }
    else
    {
    p6=0.01;
    y=100000*p1+100000*p2+200000*p3+200000*p4+400000*p5+(x-1000000)*p6;
    printf("奖金总数为:10.2f%.\n",y);
    }
    return 0;
}

你的if语句有多条语句，需要加上花括号{}