{[(x²-4)/(x²-4x+4)]+(2-x)/(x+2)}/[x/(x-2)]
先化简,后求值:[(x^2-4)\/(x^2-4x+4)-x\/(x^2-2x)]*[x-(4\/x)]
=1-(x^2-2x)\/(x^2-4x+4)=1-x(x-2)\/(x-2)^2 =1-x\/(x-2) 这步可以采用直接变为(x-2-x)\/(x-2)=1-(x-2+2)\/(x-2) 看你自己哪种方法顺手了 =1-[1+2\/(x-2)]=2\/(2-x)
X的平方-4\/x的平方-4x+4 -X-2\/X+2的计算过程
(x²-4)\/(x²-4x+4)-(x-2)\/(x+2)=[(x+2)(x-2)]\/(x-2)²-(x-2)\/(x+2)=(x+2)\/(x-2)-(x-2)\/(x+2)=[(x+2)²-(x-2)²]\/[(x+2)(x-2)]=[(x+2+x-2)(x+2-x+2)]\/(x²-4)=8x\/(x²-4)很高兴为您解答,祝...
求极限lim(x→∞)2x^2-x\/x^2+4
2014-03-17 求极限lim(1+2\/x)^2x+3 2014-05-06 求极限:lim(n→∞)(x+1)(x-2)\/(2x+1)(... 2014-03-20 求极限 lim x→(2\/π)(tanx)^(2x-π) 3 2013-10-12 lim x→∞2x+1\/x 和lim x→0 1-x^2\/1... 3 2014-01-06 求极限lim(x→4)√(2x+1)-3\/(√x-2),要详....
化简(x^2-4x+4)\/(x^2-2x)÷(x^2-4)\/x
(x^2-4x+4)\/(x^2-2x)÷(x^2-4)\/x =(x-2)²\/x(x-2)×x\/(x+2)(x-2)=1\/(x+2)如果本题有什么不明白可以追问,如果满意记得采纳 如果有其他问题请采纳本题后另发点击向我求助,答题不易,请谅解,谢谢。祝学习进步 ...
化简:(x^2\/x^2-4)×[(2+x\/x^2-2x)-(1\/x-2)]=?
[x^2\/(x+2)×(x-2)]×[2+x\/x(x-2)-1\/x-2]然后用左边的分别和后面的括号里的相乘,x\/(x-2)^2-x^2\/(x+2)(x-2)^2因为两个部分分母都有(x-2)^2所以就可以相减,最后结果是x^2-x\/x+1
若X大于2,求(x^2-3x+4)\/(x-2)的最小值,并求取最小值时x的值
把分式化简一下:(x^2-3x+4)\/(x-2)=(x^2-4x+4+x-2+2)\/(x-2)=(x-2)+1+2\/(x-2)运用平均值不等式得到(x-2)+2\/(x-2)+1>=2√2+1,等式成立当且仅当x-2=2\/(x-2),即x=2+√2时成立所以原式的最小值是2√2+1,取最小值的x是2+√2 ...
{(X+根号2)\/(x-2)}\/{(x^2+4x+4)\/(x^2-4)},其中x满足(x-2)(x+2)=0...
先从最下面开始化 (x^2+4x+4)\/(x^2-4)=(x+2)^2\/(x+2)(x-2)想必你也注意到了条件是(x-2)(x+2)=0 既然分母都等于0了,那这个式子还有意义吗
先化简,再求值:X^2-4X+4\/X^2+X\/(3\/X+1-X+1)+1\/X+2,其中X为方程X^2+...
(X^2-4X+4)\/(X^2+X)÷[3\/(X+1) -X+1] + 1\/(X+2)=(x-2)²\/[x(x+1)] ÷[(3-x²+1)\/(x+1)] + 1\/(X+2)=(x-2)²\/[x(x+1)] *(x+1)\/[-(x+2)(x-2)] + 1\/(X+2)=(x-2)\/[-x(x+2)] + 1\/(x+2)=(-x+2+x)\/[x(x+2)]...
分式计算题!急求 x^2-1\/x^2-4x+4÷(x+1)×x^2-3x+2\/x-1=?
B
(x+2\/x^2-2x-x-1\/x^2-4x+4)除以4-x\/x2-4
=[(x+2)\/x(x-2)-(x-1)\/(x-2)²] ×(x+2)(x-2)\/(4-x)=[(x+2)(x-2)-x(x-1)]\/x(x-2)² ×(x+2)(x-2)\/(4-x)=(x²-4-x²+x)\/x(x-2)×(x+2)\/(4-x)=(x-4)\/x(x-2)×(x+2)\/(4-x)=-(x+2)\/x(x-2)