第1个回答 2013-07-08
首先答案是ebcefg不是ebcegf
strcat(s1,s2);为止,s1是abcefg, s2是efg
然后I++这东西是先原值,下次用到时加一
也就是 S1[0]=a!='\0' s2[1]=s1[1]=b;
s1[1]=b!='\0' s2[2]=s1[2]=c;
s1[2]=c!='\0' s2[3]=s1[3]=e;
s1[3]=e!='\0' s2[4]=s1[4]=f;
s1[4]=f!='\0' s2[5]=s1[5]=g;
s1[5]=g!='\0' s2[6]=s1[6]='/0';
而s2[0]=e;
所以s2就是ebcefg了