= (x+1)/x ÷ [2x² -(x²+1)]/2x
=(x+1)/x ÷ (x²-1)/2x
=(x+1)/x × 2x/(x+1)(x-1)
=2/(x-1)
将x=√2 +1代入上式
原式=2/(√2+1-1)
=√2
化简,再求值,X分之X+1除(X-2X分之1+X的平方),其中X=根号2+1
=(x+1)\/x × 2x\/(x+1)(x-1)=2\/(x-1)将x=√2 +1代入上式 原式=2\/(√2+1-1)=√2
先化简,在求值:x+1\/x\/{x-(1+(1+x^\/2X)}其中x=根号2+1
=(x+1)\/x×[2x\/(x-1)(x+1)]=2\/(x-1)因为x=√2+1 所以 原式=2\/√2=√2。
先化简,再求值:x+1\/x除以(x- 1+x²\/2x),其中x=根号2+1
x+1\/x除以（x- 1+x²\/2x）=(x+1)\/x÷(2x^2-1-x^2)\/2x =2(x+1)\/(x^2-1)=2(x+1)\/(x+1)(x-1)=2\/(x-1)已知x=√2+1 x-1=√2 代入得原式=2\/√2=√2
先化简再求值x分之1+x除(x-(1+x平方)\/x平方),其中x=根号2加1
=[(x-1)+(x+1\/x)(x-1\/x)] \/ [x(x-1)-1\/x]x值比较特殊， x=√2+1, 所以x的倒数1\/x=√2-1 这样代入的时候就是比较容易求值了 =[√2+2√2.2] \/ [(√2+1).√2-(√2-1)]=5√2 \/ (2+√2-√2+1)=5√2 \/ 3 ...
先化简,再求值:x+1∕x除以(1+x的平方∕2x),其中x=根号2+1
=x+1\/x乘（2X\/X+1的平方）=X的平方+1\/X乘（2X\/X+1的平方）=X-1\/X乘2X\/X+1 =X-1\/1乘2\/X+1 =2X-2\/X+1 把X=根号2+1代入式子得 =2（2+1）-2\/2+1+1 =4+2-2\/4 =4\/4 =1
...分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1
:[(x²-2x+1)分之x]÷[(x²-1)分之(x+1)+1],其中x=根号2+1 =[x\/(x-1)²]÷[(x+1)\/(x-1)(x+1)+1]=[x\/(x-1)²]÷[1\/(x-1)+1]=[x\/(x-1)²]÷[(1+x-1)\/(x-1)]=[x\/(x-1)²]÷[x\/(x-1)]=1\/(x-1)=1\/(√2...
x+1分之x^2-x÷x+1分之x,其中x=根号2+1
原式=x（x-1）\/(x+1)÷x\/（x+1）=x-1 =√2+1-1 =√2 请好评 ~在右上角点击【评价】，然后就可以选择【满意，问题已经完美解决】了。如果你认可我的回答，敬请及时采纳，~你的采纳是我前进的动力~~
先化简,再求值:(1\/(x+1)+(x^2-2x+1)\/(x^2-1)\/(x-1)\/(x+1),其中x=3
1\/（x+1）+（x^2-2x+1）\/（x^2-1)\/（x-1）\/（x+1）=1\/(x+1)+(x-1)²\/(x+1)(x-1)×(x+1)\/(x-1)=1\/(x+1)+1 =(x+2)\/(x+1)当x=3时 原式=5\/4 [1\/（x+1）+（x^2-2x+1）\/（x^2-1)]\/（x-1）\/（x+1）=[1\/(x+1)+(x-1)²\/(x+...
先化简,再求值(1+1-x\/x+1)÷2x-2\/x+2x+1,其中x=√2+1?
(1 + 1 - x\/x + 1) ÷ (2x - 2\/x + 2x + 1)根据给定的x=√2+1，我们将x的值代入表达式中，得到：(1 + 1 - (√2 + 1)\/(√2 + 1) + 1) ÷ (2(√2 + 1) - 2\/(√2 + 1) + 2(√2 + 1) + 1)继续化简，我们可以将分子中的一些项合并：(2 - (√2 + 1...
...之x的平方+2x+1除以x-1分之x的平方-1其中x=根号2-2
原式=[1\/(x+2)]-[(x+2x+1)\/(x+2)]÷[(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷[(x+1)(x-1)\/(x-1)] =[1\/(x+2)]-[(x+1)\/(x+2)]÷(x+1) =[1\/(x+2)]-[(x+1)\/(x+2)]×[1\/(x+1)] =[1\/(x+2)...
