-(x^2-y^2)(x+y)-(y-x)^3
=-(x+y)(x-y)(x+y)+(x-y)^3
=(x-y)[-(x+y)^2+(x-y)^2]
=(x-y)[(x-y)^2-(x+y)^2]
=(x-y)[(x-y)-(x+y)][(x-y)+(x+y)]
=(x-y)(-2y)(2x)
=-4xy(x-y)
=4xy(y-x)追答
不懂追问
追问好像不是这样的
追答哪里不懂
追问(y-x)^3不等(x-y)^3
是吗？
追答前面有个负号
-(y-x)^3
=[-(y-x)]^3
=(x-y)^3
我已经解出来了
追答答案一样就采纳
追问噢
追答不懂就追问，等下回答
本回答被提问者采纳因式分解:(x的平方-y的平方)(x+y)-(x-y)的三次方?
=(x+y)(x-y)(x+y)-(x-y)*(x-y)^2 =(x^2+2xy+y^2)(x-y)-(x^2-2xy+y^2)(x-y)=(x^2+2xy+y^2-x^2+2xy-y^2)(x-y)=4xy(x-y),2,
x^2-y^2-(x+y)^2,因式分解
x^2-y^2-(x+y)^2 =(x-y)(x+y)-(x+y)^2 =(x-y-x-y)(x+y)=-2y(x+y)
-x^2+y^2因式分解
原式=y^-x^=(y-x)(y+x)
x^2-y^2-x-y 因式分解
=(x^2-y^2)-(x+y) 【分组分解】=(x+y)(x-y)-(x+y) 【平方差公式】=(x+y)(x-y-1) 【提取公因式(x+y) 】
数学:-x^2-y^2能因式分解吗?提取-1变成(x^2+y^2)不叫因式分解吗?教材上...
-x^2-y^2不能因式分解了。因式分解后应该是几个因式的乘积，而因式则是含有字母的式子，因式分解的例子：-x^2-y^2-2xy=-(x+y)^2 这个就分解成了两个x+y相乘，还有一个因数-1。再如：x^2-2x-3=(x-3)(x+1)你提问的那个，只是提出个-1，本质上还是原来的式子，没有改变，所以不叫...
因式分解 (x^2-y^2)(x-y)^2-(x-y)^4
(x^2-y^2)(x-y)^2-(x-y)^4 =(x-y)^2[(x^2-y^2)-(x-y)^2]=(x-y)^2(x^2-y^2-x^2+2xy-y^2)=(x-y)^2(-2y^2+2xy)=2y(x-y)^2(x-y)=2y(x-y)^3
利用因式分解计算:(x^2-y^2)-(x-y)^2
解：(x^2-y^2)-(x-y)^2 ＝（x+y）（x-y）-（x-y）²=(x-y)[(x+y)-(x-y)]=(x-y)(2y)=2y(x-y)
X^2-Y^2-X+Y=?
X^2-Y^2-X+Y =(x+y)(x-y)-(x-y)=(x+y-1)(x-y)A^2+2AB+B^2-1 =(A+B)^2-1^2 =(A+B+1)(A+B-1)
(x^2-y^2)(x+y)=(x-y)( )
左边=(x+y)(x-y)(x+y)=（x-y)(x+y)^2 所以空格里填x加y括号的平方
-xy^2(x+y)^3+x(x+y)^2因式分解
-xy^2(x+y)^3+x(x+y)^2 =x(x+y)^2[(-y^2(x+y)+1)]=x(x+y)^2(1-xy^2-y^3)
