1/6+1/12+1/20+1/30+1/40怎样简算

如题所述

每个分数都把分母扩大到120再算然后化简
温馨提示:内容为网友见解,仅供参考
第1个回答  2014-05-19
=1/2一1/3+1/3一1/4+1/4一1/5+1/5一1/6+1/40=1/2一1/6+1/40=1/3+1/40=43/120
第2个回答  2014-05-19
3/12+3/40+1/30=15/60+2/60=17/60
第3个回答  2014-05-19
1/6=1/2 × 1/3 ,1/12=1/3 × 1/4,1/20=1/4 ×1/5,1/30=1/5 ×1/6,1/40=1/5 × 1/8,所以原式=1/2×1/3+1/3×1/4+1/4×1/5+1/5×1/6+1/5×1/8=43/120追答

1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/5+(1/3)×(1/5-1/8)=43/120

1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+(1/3)×(1/5-1/8)=43/120

第4个回答  2014-05-19
1/(6+12+20+30+40)
第5个回答  2014-05-19

1\/6+1\/12+1\/20+1\/30+1\/40怎样简算
每个分数都把分母扩大到120再算然后化简

1\/6+1\/12+1\/20+1\/30+1\/42 简算
=(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+(1\/5-1\/6)+(1\/6-1\/7)去掉括号=1\/2-1\/7=2\/14

1\/6+1\/12+1\/20+1\/30+1\/42(简算) 急!!
=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7 =1\/2-1\/7 =7\/14-2\/14 =5\/14

1\/6 1\/12 1\/20 1\/30 1\/42等于多少过程?
釆用裂项求和法简算:1\/6+1\/12+1\/20+1\/30+1\/42 =1\/(2×3)+1\/(3×4)+1\/(4×5)+1\/(5×6)+1\/(6×7)=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7 =1\/2-1\/7 =5\/14

简算:1\/6+1\/12+1\/20+1\/30+1\/42+1\/56+1\/72+1\/90
注意到1\/6=1\/2*3=1\/2-1\/3,1\/12=1\/3*4=1\/3-1\/4,同理1\/20=1\/4-1\/5,1\/30=1\/5-1\/6,1\/42=1\/6-1\/7,1\/56=1\/7-1\/8,1\/72=1\/8-1\/9,1\/92=1\/9-1\/10.全部相加中间的都消去了,只剩1\/2-1\/10=2\/5

1\/2十1\/6十1\/12十1\/20十l\/30再加1\/40简算
简便方法计算如下:1\/2+1\/6+1\/12+1\/20+1\/30+1\/40 =1\/2+(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+(1\/5-1\/6)+1\/40 =1\/2+1\/2 -1\/6 +1\/40 =1- 1\/6 +1\/40 =1-(20-3)\/120 =1-17\/120 =103\/120

1\/2十1\/6十1\/12十1\/20十l\/30再加1\/40简算
简便方法计算如下:1\/2+1\/6+1\/12+1\/20+1\/30+1\/40 =1\/2+(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+(1\/5-1\/6)+1\/40 =1\/2+1\/2 -1\/6 +1\/40 =1- 1\/6 +1\/40 =1-(20-3)\/120 =1-17\/120 =103\/120

1\/6+1\/12+1\/20+1\/30+1\/42+1\/56=?
简算 1\/6+1\/12+1\/20+1\/30+1\/42+1\/56 =1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7+1\/7-1\/8 =1\/2-1\/8 =3\/8

一道简算题 1\/6+1\/12+1\/20+1\/30+1\/42+1\/56+1\/72+1\/90+1\/110
根据1\/(a*b)=1\/a-1\/b可解1\/6+1\/12+1\/20+1\/30+1\/42+1\/56+1\/72+1\/90+1\/110 原式=1\/(2*3)+1\/(3*4)+1\/(4*5)+……+1\/(10*11)=1\/2-1\/3+1\/3-1\/4+……+1\/10-1\/11=1\/2-1\/11 =11\/22-2\/22=9\/22 ...

六分之一+十二分之一+二十分之一+三十分之一+四十二分之一+五十六分之...
解:1\/6+1\/12+1\/20+1\/30+1\/42+1\/56+1\/72+1\/90 =1\/(2x3)+1\/(3x4)+1\/(4x5)+1\/(5x6)+1\/(6x7)+1\/(7x8)+1\/(8x9)+1\/(9x10)=(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+(1\/5-1\/6)+(1\/6-1\/7)+(1\/7-1\/8)+(1\/8-1\/9)+(1\/9-1\/10)=1\/2-1\/10 =2...

相似回答