C++高手来！！编写一个Complex类，需要完成的运算符重载有： + ：重载+，用来完成两个复数的加法

Question

编写一个Complex类，需要完成的运算符重载有：
(1) + ：重载+，用来完成两个复数的加法；
(2) - ：重载 - ，用来完成两个复数的减法；
(3) *：重载*，用来完成两个复数的乘法；
(4) <<：重载<<，用来输出一个复数，输出的格式为(a + b * i)，其中a为实部，b为虚部。
还有一个 程序的输入输出和测试程序
编写一个驱动程序来测试Complex类的运算符重载，测试程序要测试所有的运算符重载，测试程序的样例程序请参见给出的代码。

Answer 1

#include <iostream>
#include <assert.h>
class Complex
{
public:
Complex(float a,float b)
:m_real(a)
,m_imaginary(b)
{
}
Complex()
:m_real(0)
,m_imaginary(0)
{
}
const Complex operator+(const Complex& other)
{
Complex c(m_real+other.m_real,m_imaginary+other.m_imaginary);
return c;
}
const Complex operator-(const Complex& other)
{
Complex c(m_real-other.m_real,m_imaginary-other.m_imaginary);
return c;
}
const Complex operator*(const Complex& other)
{
Complex c(m_real*other.m_real-m_imaginary*other.m_imaginary,m_imaginary*other.m_real+m_real*other.m_imaginary);
return c;
}
float m_real,m_imaginary;
};
std::ostream& operator<<(std::ostream& o,const Complex& c)
{
o<<c.m_real<<'+'<<c.m_imaginary<<"*i";
return o;
}

//测试

int main(int argc, char *argv[])
{
Complex a(3.5,2.0);
Complex b(2.0,8.5);
Complex c;
c=a+b;
assert(c.m_real==5.5);
assert(c.m_imaginary==10.5);
c=a-b;
assert(c.m_real==1.5);
assert(c.m_imaginary==-6.5);
c=a*b;
assert(c.m_real==-10.0);
assert(c.m_imaginary==33.75);
std::cout<<c<<std::endl;
return 0;
}

Answer 2

请问：你那个给出的代码是什么？