编程java编写程序实现键盘输入1~100之间的整数,根据提示信息才出电脑产生的随机数？

Answer 1

import java.util.Scanner;

public class test {

public static void main(String[] args) {
int i = (int) (Math.random() * 100 + 1);
int j = 2;
int x = 1;
boolean flag = true;
while (x != 0) {
while (flag) {
Scanner scan = new Scanner(System.in);
if (scan.hasNextInt()) {
// 判断输入的是否是整数
j = scan.nextInt();
} else {
// 输入错误的信息
System.out.println("输入的不是整数！,请重新输入");
continue;
}
flag = false;
}
x = comper(j, i);
if (x == -1) {
System.out.println("小了");
} else if (x == 1) {
System.out.println("大了");
} else {
System.out.println("正确");
}
flag = true;
}
}

public static int comper(int j, int i) {
if (j > i) {
return 1;
} else if (i == j) {
return 0;
}
return -1;
}
}