分解因式x3-xy2+x2y-y3

如题所述

第1个回答  2013-01-21
x3-xy2+x2y-y3
原式=(x^3+x^2y)-(xy^2+y^3)
=x^2(x+y)-y^2(x+y)
=(x+y)(x^2-y^2)
=(x+y)(x+y)(x-y)
=(x+y)^2(x-y)
第2个回答  2013-01-21
x3-xy2+x2y-y3
=x(x^2-y^2)+y(x^2-y^2)
=(x^2-y^2)(x+y)
=(x+y)^2(x-y)本回答被提问者采纳
第3个回答  2013-01-21
x3-xy2+x2y-y3
=(x3-xy2)+(x2y-y3)
=x(x²-y²)+y(x²-y²)
=(x²-y²)(x+y)
=(x-y)(x+y)²
第4个回答  2013-01-21
x^3-xy^2+x^2y-y^3
=(x^3-y^3)+(x^2y-xy^2)
=(x-y)(x^2+xy+y^2)+xy(x-y)
=(x-y)(x^2+2xy+y^2)
=(x-y)(x+y)^2

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如图

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