计算(1)-1的四次方-(1-0.5)*1/3*[2-(-3²)]

(2)-2²*(-1/2)+8/(-2)²
(3)(7/9-5/6+11/18)*18-1.45*6+3.95*6
(4)4又1/2*[-9*(-1/3)²-0.8]/(-5又1/4)
*=乘号
/=除号

第1个回答  2013-07-22
=1-0.5*1/3*-7
=1-0.5/3-7
=-6-0.5/3
=-18/3-0.5/3
=-18.5/3
答案应该是负的三分之十八点五。
第2个回答  2013-07-22
(1)-1的四次方-(1-0.5)*1/3*[2-(-3²)]
=1-1/2×1/3×(-7)
=1+7/6
=2又1/6

(2)-2²*(-1/2)+8/(-2)²

=-4×(-1/2)+2
=2+2
=4
(3)(7/9-5/6+11/18)*18-1.45*6+3.95*6

=7/9×18-5/6×18+11/18×18-(1.45-3.95)×6
=14-15+11-(-2.5)×6
=14-15+11+15
=25
(4)4又1/2*[-9*(-1/3)²-0.8]/(-5又1/4)

=4½×(-9×1/9-0.8)/(-5¼)
=9/2×(-9/5)×(-4/21)
=54/35本回答被提问者采纳

计算(1)-1的四次方-(1-0.5)*1\/3*[2-(-3²)]
=1-0.5*1\/3*-7 =1-0.5\/3-7 =-6-0.5\/3 =-18\/3-0.5\/3 =-18.5\/3 答案应该是负的三分之十八点五。

-1的4次方-(1-0.5)x3分之1-[2-(-3)的2次方]怎么算
(-1)的四次方-(1-0.5)×1\/3-[2-(-3)²]=-1-1\/6-(2-9)=-1-1\/6+7=6-1\/6=35\/6

计算:-1的四次方-(1-0.5)×1\/3×<2-(-3)²>
的6分之13

(-1)^4-(1-0.5)×1\/3×{2-(-2)^2}=?
解:原式 =1-1\/2x1\/3x(2-4)=1+1\/2x1\/3x2 =1+1\/3 =4\/3 (3分之4)

-1的4次方-(1-0.5)*1\/3*[2-(-3)的2次方] 过程
-1的4次方-(1-0.5)*1\/3*[2-(-3)的2次方]=1-0.5×1\/3×(2-9)=1-1\/6×7 =1-6\/7 =1\/7

(-1)的4次方-(1-0.5)乘3分之1乘【2-(-2)的2次方】等于多少?
(-1)的4次方-(1-0.5)乘3分之1乘【2-(-2)的2次方】=1-0.5×1\/3×【2-4】=1+0.5×1\/3×2 =1+1\/3 =4\/3

要过程和答案 -1的4次方-(1-0.5)×三分之一×[2-﹙-3﹚的次方]
-1的4次方-(1-0.5)×三分之一×[2-﹙-3﹚的2次方]=-1-0.5x1\/3x[2-9]=-1-1\/6x(-7)=-1+7\/6 =1\/6

-1的四次方减(1-0点5)×1\/3×[2减(-3)的二次方]
-1的4次方-(1-0.5)×1\/3×[2-(-3)的2次方]=-1-0.5×1\/3×[2-9]=-1-1\/6×(-7)=-1+7\/6 =1\/6

数学题: -1的4次方-(1-0.5)X3分之1X[2-(-3)的2次方] (要过程)
-1的4次方-(1-0.5)X3分之1X[2-(-3)的2次方]=1-(1\/2)x(1\/3)x(2-9)=1-(1\/6)x(-7)= 1+7\/6 =13\/6 =1又6\/7

-1的四次方-(1-0.5)×1\/3×[2-(-2)的二次方]
-1的四次方-(1-0.5)×1\/3×[2-(-2)的二次方]=-1-0.5*(1\/3)*(2+4)=-1-0.5*2 =-2;

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