mysql中一个字段同时满足多个条件,(3个以上)

Question

mysql中一个字段同时满足多个条件,(3个以上),该如何写???用or的话 连接只能连接两个
不是同时,额,是满足就行, 我用or的时候只能放三个条件,然后 跟上order by
id desc

select * from message where (typeid=31) or (typeid=30) or (typeid=32) or <typeid=33) order by id desc;

次偶 typeid前面变成<,所以才出错= =

Answer 1

SELECT

t.file_id

FROM

app_polly_file_labels t

WHERE

t.style = '清新'

or t.style = '甜美'

or t.style = '韩潮来袭'

GROUP BY t.file_id

HAVING count(t.file_id)=3

或者

SELECT

a.file_id

FROM

app_polly_file_labels a

INNER JOIN app_polly_file_labels b ON a.file_id = b.file_id

INNER JOIN app_polly_file_labels c  ON a.file_id = c.file_id

WHERE

a.style ='清新'

AND b.style ='甜美'

AND c.style ='韩潮来袭'

扩展资料：

sql常用的复杂查询语句

一、选择指定的列

select Sno as 学号,Sname as 姓名 from student

select Sno,Sname from student

二、查询全部列

select * from student

三、对查询后的指定列进行命名

select Sname as 姓名,(2014-Sage) as 出生年 from student

select Sname ,(2014-Sage) from student

四、消除取值重复的行

select distinct Sno as 选修了课程的学生学号 from SC

select distinct Sno from SC

五、选择表中若干元组，满足条件的

select Sname as 学生姓名 from student where Sdept='IS'

参考链接：SQL语句大全

Answer 2

select * from message where (typeid=31) or (typeid=30) or (typeid=32) or (typeid=33) order by id desc;

或者

select * from message where typeid IN ( 31, 30, 32, 33) order by id desc;

Answer 3

同时满足用 and
select * from message where (typeid=31) and (typeid=30) and (typeid=32) and <typeid=33) order by id desc;