C语言编程题

Question

已知银行整存整取存款不同期限的月息利率分别为：
0.63% 期限一年
0.66% 期限二年
月息利率= 0.69% 期限三年
0.75% 期限五年
0.84% 期限八年
要求输入存钱的本金和期限，求到期时能从银行的到的利息与本金的合计。

Answer 1

#include <stdio.h>
void main()
{
float n,s;
int m,i;
float a=0.0063,b=0.0066,c=0.0069,d=0.0075,e=0.0085;
printf("请输入本金:");
scanf("%f",&n);
printf("\n请输入年限:");
scanf("%d",&m);
s=n;
if(m==1)
{
s=s+n*a*12;
printf("\n%d年后本利为%f元",m,s);
}
if(m==2)
{
s=(s+n*b*12)*b*12;
printf("\n%d年后本利为%f元",m,s);
}
if(m>=3&&m<5)
{
for(i=3;i<5;i++) s=s+s*c*12;
printf("\n%d年后本利为%f元",m,s);
}
if(m>=5&&m<8)
{
for(i=5;i<8;i++) s=s+s*c*12;
printf("\n%d年后本利为%f元",m,s);
}
if(m>=8)
{
for(i=8;i<m;i++) s=s+s*c*12;
printf("\n%d年后本利为%f元",m,s);
}
}

你看看有错没,有的话我再修改

Answer 2

#include <stdio.h>

float money(int year, int m);

int main()
{
int y, m;
printf("Please input the money and the year:\n");
scanf("%d %d", &y, &m);
printf("The total money you will get is:\n%f", money(y, m));

return 0;
}

float money(int year, int m)
{
switch (year)
{
case 1:
return (m*12*0.0063+m);
case 2:
return (2*m*12*0.0066+m);
case 3:
return (3*m*12*0.0069+m);
case 5:
return (5*m*12*0.0075+m);
case 8:
return (8*m*12*0.0084+m);
}
}