用C语言编写程序，输入一个正整数，判断是否为回文数。

Answer 1

main()

{

int n,a,b=0;

printf("please enter a number !\n");

scanf("%d",&n);

printf("the number is %d\n",n);

for(a=n;a>0;){

b=b*10+a%10;

a=a/10;

}

printf("n=%d,b=%d\n",n,b);

if(b==n){

printf("yes!!!");

}else{

printf("yes!!!");

}

}

Answer 2

#include ＂Stdio.h＂

#include ＂Conio.h＂

int main(void)

{

int i,k;

long n,m;

int digit[10];

clrscr();

puts(＂Please input a long number:＂);

scanf(＂%ld＂,&n);

m=n;k=0;

do

{

digit[k++]=m%10; /**//*保存最低位*/

m/=10; /**//*去掉最低位*/

}while(m!=0);

k--;

for(i=0;i<k;i++,k--) /**//*判断是否为回文数*/

if(digit[i]!=digit[k]) break; /**//*不相等,则不是回文数,推出循环*/

if(i<k) printf(＂%ld is not a huiwen number＂,n);

else printf(＂%ld is a huiwen number＂,n);

getch();

return 0;

}

Answer 3

# include <stdio.h>

int main(void){
int val;
int m;
int sum = 0;
printf("请输入您需要判断的数字:");
scanf("%d",&val);
m = val;
while (m){
sum = sum * 10 + m%10;
m /=10;
}
if(sum == val){
printf("Yes!\n");
}else{
printf("No!\n");
}
return 0;

}