C语言编程，使用Input(), sum(), output()三个函数，编制可以输入两数，显示出两数之和的程序

Question

求教程。。。
要包括上面三个函数，而且要是运行者输入两个数，程序就能算出其两数之和并显示的程序

Answer 1

楼主你好

具体代码如下:
#include<stdio.h>
void input(int *a,int *b){
printf("输入两个整数:");
scanf("%d %d",a,b);
}
int sum(int a,int b){
return a+b;
}
void output(int s){
printf("它们的和为:%d\n",s);
}
int main()
{
int a,b;
input(&a,&b);
output(sum(a,b));
return 0;
}

希望能帮助你哈

Answer 2

#include <stdio.h>
int x = 0;
int y = 0;
int Sum = 0;
void input()
{
printf("input x , y\n");
scanf("%d %d",&x ,&y);
}
void sum()
{
Sum = x + y;
}
void output()
{
printf("Sum=%d\n",Sum);
}
void main()
{
input();
sum();
output();
}

Answer 3

版本1：

#include "stdlib.h"
void input( int* factor1, int* factor2 )
{
if ( !factor1 || !factor2 ){
return;
}
printf("input the first one:\t");
scanf("%d",factor1);
printf("\n");
printf("input the second one:\t");
scanf("%d",factor2);
printf("\n");
}
void sum( int* sum_d, int* factor1, int* factor2 )
{
if( !sum_d || !factor1 || !factor2 ){
return;
}
*sum_d = *factor1 + *factor2;
}
void output( int* sum_d, int* factor1, int* factor2 )
{
if( !sum_d || !factor1 || !factor2 ){
return;
}
printf("\n%d + %d = %d\n",*factor1,*factor2,*sum_d);
}
int main(int argc, char const *argv[])
{
int factor1 = 0;
int factor2 = 0;
int sum_d = 0;
input(&amp;factor1,&amp;factor2);
sum(&amp;sum_d,&amp;factor1,&amp;factor2);
output(&amp;sum_d,&amp;factor1,&amp;factor2);
return 0;
}

版本2：

#include "stdlib.h"
int factor1 = 0;
int factor2 = 0;
int sum_d = 0;
void input( void )
{
printf("input the first one:\t");
scanf("%d",&factor1);
printf("\n");
printf("input the second one:\t");
scanf("%d",&factor2);
printf("\n");
}
void sum( void )
{
sum_d = factor1 + factor2;
}
void output( void )
{
printf("\n%d + %d = %d\n",factor1,factor2,sum_d);
}
int main(int argc, char const *argv[])
{
input();
sum();
output();
return 0;
}

Answer 4

。。。。。这个太简单了。你自己想好点。Input()里面写输入，sum()里面求和，output()里面写输出。然后写个主程序在把他们调用下就行了！

Answer 5

很简单的。。。