=(x+y)[(x^2-xy+y^2)-2y^2]
=(x+y)(x^2-xy+y^2)-(x+y)*2y^2
=x^3+y^3-2xy^2-2y^3
=x^3-2xy^2-y^3本回答被提问者采纳
因式分解 (x+y)(x^2-xy-y^2)
=(x+y)[(x^2-xy+y^2)-2y^2]=(x+y)(x^2-xy+y^2)-(x+y)*2y^2 =x^3+y^3-2xy^2-2y^3 =x^3-2xy^2-y^3
(x+y)(x^2-xy+y^2)
x^3+y^3=(x+y)(x^2-xy+y^2)这是个公式
(x+y)(x^2-xy+y^2)要因式分解全过程!可追加分!
原式=x^3-y*x^2+x*y^2+y*x^2-x*y^2+y^3=x^3+y^3 望采纳。。。
x平方+XY+-Y平方因式分解
x^3+y^3=(x+y)(x^2-xy+y^2)x^3-y^3=(x-y)(x^2+xy+y^2)
(x+y)(x-1)-xy-y^2 怎么因式分解??
=xx-x-y-yy =(x-y)(x+y)-(x+y)=(x-y-1)(x+y),2,=x2-x+xy-y-xy-y2 =x2-x-y-y2 =(x-y)(x+y)-(x+y)=(x+y)(x-y-1),2,(x+y)*(x-1)-x*y-y*y=(x+y)*(x-1)-(x+y)*y=(x+y)*(x-y-1),2,（x+y）(x-1)-xy-y^2 =（x+y）(x-1)-...
因式分解(x+y)^2-(x-y)^2
(x+y)²-(x-y)²=(x+y-x+y)(x+y+x-y)=2y×2x =4xy 是因式分解
求满足x+y+z=1,x3+y3+z2=1的所有整数解
采用因式分解即可得到答案。解：由题意，,x3+y3=(x+y)(x^2-xy+y^2)=1-z^2=(1+z)(1-z)=(x+y)(1+z)(1)z=1,x=k,y=-k,k∈Z。(2)z≠1,z=x^2-xy+y^2-1 x+y+x^2-xy+y^2=2 x^2-(y-1)x+y^2+y-2=0 ∵x,y∈Z，∴Δ=-3(y+1)^2+12是完全平方数且...
因式分解(x-2y)(x+y)(x2-xy+y2)过程和答案
(x-2y)(x+y)(x2-xy+y2)(后面两个括号里是立方和公式)=（X-2Y）(X^3+Y^3)=X^4+XY^4-2XY^3-2Y^4 参考资料：后面两个括号里是
因式分解 X^2-XY-Y^2,在线求解
x^2-xy-y^2 =(x-y\/2)^2-y^2\/4-y^2 （此步为配方法）=(x-y\/2)^2-5y^2\/4 =(x-y\/2)^2-(√5y\/2)^2 =(x-y\/2+√5y\/2)(x-y\/2-√5y\/2) （此步为平方差公式）
x^3-xy^2+xy+y^2,因式分解
解：原式=x^3+x^2y-x^2y-xy^2+xy+y^2 =x^2(x+y)-xy(x+y)+y(x+y)=(x+y)(x^2-xy+y)
