=30*(-1/30)/(2/3-1/10+1/6-2/5)*30
=(-1)/(20-3+5-12)
=(-1)/10
=-1/10
=(-1/30)(3/2-10+6-5/2)
=-1/20+1/3-1/5+1/12
=-1/4+5/12
=-3/12+5/12
=2/12
=1/6
(-1\/30)\/(2\/3-1\/10+1\/6-2\/5) 不要来给我通分、也别来个什么“除法分配律...
=(-1)\/10 =-1\/10
(-1\/30)÷(2\/3-1\/10+1\/6-2\/5)计算怎样算?
其实很简单，先算括号内的加减，最后算外边的除法，具体算法如下：
(—1\/30)÷(2\/3-1\/10+1\/6-2\/5)的两种方法计算
=（-1\/30)÷[10\/30]=（-1\/30)*3 = -1\/10 一楼说的不对,除法无分配律（被乘数要分配时可转化为乘法)
(-1\/30)\/(2\/3-1\/10+1\/6-2\/5) 求过程
先（—1\/30）等于—1\/30，后面的把它全部通分成（20\/30—3\/30+5\/30—12\/30）等于10\/30，即1\/3，最后把—1\/30乘以1\/3等于—1\/90。所以最后等于—1\/90
下面是某同学计算(- 1 30 )÷( 2 3 - 1 10 + 1 6 - 2 5 )的过程:
解：（-130）÷（23-110+16-25）=（-130）÷（-96）=65\/48
(-1\/30)除以(2\/3-1\/10+1\/6-2\/5).巧算
(-1\/30)除以（2\/3-1\/10+1\/6-2\/5).=-1÷【（2\/3-1\/10+1\/6-2\/5)÷1\/30】= -1÷【（2\/3-1\/10+1\/6-2\/5）×30】= -1÷【2\/3×30-1\/10×30+1\/6×30-2\/5×30】= -1÷【20-3+5-12】= -1÷10 = -1\/10 ...
(-1\/30)÷[﹙2\/3﹚-﹙1\/10﹚+﹙1\/6﹚-﹙2\/5﹚]的简便算法
解：原式=(-1\/30)÷[(2\/3+1\/6)-(1\/10+2\/5)]=(-1\/30)÷(5\/6-1\/2)=(-1\/30)÷(1\/3)=(-1\/30)×3 = -1\/10
(-1\/30)÷(2\/3-1\/10+1\/6-2\/5)
回答：-10分之1
巧解(-1\/30)\/(2\/3-1\/10+1\/6-2\/5)。要用倒数及分配率来解。
的倒数为：（2\/3-1\/10+1\/6-2\/5）\/（-1\/30）则：（2\/3-1\/10+1\/6-2\/5）\/（-1\/30）=（2\/3-1\/10+1\/6-2\/5）×（-30）=-30×2\/3+30×1\/10-30×1\/6+30×2\/5 = -20+3-5+12 = -10 则（-1\/30）\/（2\/3-1\/10+1\/6-2\/5）= -1\/10 ...
(-1\/30)除以(2\/3-1\/10+1\/6-2\/5).巧算
(-1\/30)除以（2\/3-1\/10+1\/6-2\/5).=-1÷【（2\/3-1\/10+1\/6-2\/5)÷1\/30】= -1÷【（2\/3-1\/10+1\/6-2\/5）×30】= -1÷【2\/3×30-1\/10×30+1\/6×30-2\/5×30】= -1÷【20-3+5-12】= -1÷10 = -1\/10 ...
