原式=(x-y)^7÷(x-y)³×[-1×(x-y)]^7
=(x-y)^7÷(x-y)³×(-1)^7×(x-y)^7
=(x-y)^(7-3+7)×(-1)
= -(x-y)^11
如果是(x-y)^7/[(x-y)³×(y-x)^7]，那么
原式=(x-y)^7÷(x-y)³÷(y-x)^7
=(x-y)^7÷(x-y)³÷[-1×(x-y)]^7
=(x-y)^7÷(x-y)³÷(-1)^7÷(x-y)^7
=(x-7)^(7-3-7)÷(-1)
=-(x-7)^(-3)
= -1/(x-7)³
请选择你所需要的答案
(x-y)^7\/(x-y)^3*(y-x)^7
解：如果是[(x-y)^7\/(x-y)³]×(y-x)^7，那么 原式=(x-y)^7÷(x-y)³×[-1×(x-y)]^7 =(x-y)^7÷(x-y)³×(-1)^7×(x-y)^7 =(x-y)^(7-3+7)×(-1)= -(x-y)^11 如果是(x-y)^7\/[(x-y)³×(y-x)^7]，那么 原式=(x-...
(x-y)^7\/(x-y)^2\/(y-x)^2
(x-y)^7\/(x-y)^2\/(y-x)^2 =(x-y)^5\/(y-x)^2 =(x-y)^3
(x-y)^7除以(y-x)^3除以(y-x)^2=__
-(x-y)^2 (x-y)^7÷(y-x)^3 = (x-y)^7÷[-(x-y)^3] =-(x-y)^4 -(x-y)^4÷(y-x)^2=-(x-y)^4÷(x-y)^2=-(x-y)^2
(x-y)^7÷(y-x)^3÷(y-x)^2=?
(x-y)^7 =[-1*(y-x)]^7 =(-1)^y*(y-x)^7 =-(y-x)^7 所以原式=-(y-x)^7÷(y-x)^3÷(y-x)^2 =-(y-x)^(7-3-2)=-(y-x)^2
(x-y)7次方÷(y-x)3次方*(y-x)2次方
(x-y)7次方÷(y-x)3次方*(y-x)2次方 = (x-y)^7 ÷ (y-x)^3 * (y-x)^2 = (x-y)^7 ÷ (-1)*(x-y)^3 * (x-y)^2 = (-1)*(x-y)^4 * (x-y)^2 = (-1)*(x-y)^6 = - (x-y)^6
(x-y)^7÷(y-x)^2÷(x-y)^3
原式=(x-y)^7÷[-(x-y)]^2÷(x-y)^3 =(x-y)^7÷(x-y)^2÷(x-y)^3 =(x-y)^(7-2-3)=(x-y)^2
(x-y)的三次方*(x-y)-(y-x)的七次方等于?要过程
解：（x-y）的三次方*（x-y）-（y-x）的七次方 =（y-x）^4-（y-x）^7 =（y-x）^4[（1-（y-x）^3]
(x-y)^7(x-y)(y-x)^4=?
(x-y)^7(x-y)(y-x)^4=-(x-y)^11
计算:{(x-y)^2·(y-x)^3}^2+(y-x)^3·(x-y)^7
计算:{(x-y)^2·(y-x)^3}^2+(y-x)^3·(x-y)^7 我来答 分享 复制链接http:\/\/zhidao.baidu.com\/question\/615907452147555892 新浪微博 微信扫一扫 举报 1个回答 #热议# 国际油价闪崩,大幅度下跌是何缘故?三叶草shuying 2014-03-04 · TA获得超过8812个赞 ...
(x-y)的7次除以(y-x)的6次加(-x-y)的3次除以(x+y)
[(x-y)^7] ÷ [(y-x)^6] + [(-x-y)^3] ÷ (x+y)=[(x-y)^7] ÷ [(x-y)^6] + [-(x+y)^3] ÷ (x+y)=(x-y) - (x+y)²=x-y-x²-y²-2xy
