写一个C程序.要求随机产生10个两位数的正整数,找出其中奇数和偶数的个数,并将其排序输出.

Question

最好能附上注释,谢谢.

Answer 1

#include <stdio.h>
#include <stdlib.h>
srand();
int random(void)
{
int ret = (int)(100.0*rand()/(RAND_MAX+1.0));
while(ret < 10)
{
ret = (int)(100.0*rand()/(RAND_MAX+1.0));
}
return ret;
}

void creatArr(int *arr)
{
int i = 0;
for(;i < 10;i++)
{
arr[i] = random();
}
}

void count(int *arr)
{
int s = 0;
int d = 0;
int i = 0;
for(;i < 10;i++)
{
if(arr[i]%2)
s++;
else
d++;
}
printf("奇数有%d个\t偶数有%d个\n", s, d);
}

void SortPrint(int *arr)
{
int i, j, tmp;
printf("排序后的数组为：\n");
for(i = 0;i < 10;i++)
{
for(j = (i - 1);j > 0;j--)
{
if(arr[j] > arr[j-1])
{
tmp = arr[j-1];
arr[j-1] = arr[j];
arr[j] = tmp;
}
}
}
for(i = 0;i < 10;i++)
{
printf(" %d\n", arr[9-i]);
}
}
int main()
{
int arr[10];

creatArr(arr); //用随机数填充数组
count(arr); //数奇偶数
SortPrint(arr); //冒泡法排序输出

return 0;
}
楼主直接粘锅去用，程序很简单，注释就不多写了，自己多多研究哦

Answer 2

Dim num(20) As Integer

Private Sub Command1_Click()
Dim i As Integer
Dim num_o As Integer '奇数个数
Dim num_e As Integer '偶数个数
Dim sum_o As Integer
Dim sum_e As Integer
num_o = 0
num_e = 0
sum_o = 0
sum_e = 0
For i = 0 To 19
If num(i) Mod 2 Then
num_o = num_o + 1
sum_o = sum_o + num(i)
Text1.Text = Text1.Text + CStr(num(i)) + vbCrLf
Else
num_e = num_e + 1
sum_e = sum_e + num(i)
Text2.Text = Text2.Text + CStr(num(i)) + vbCrLf
End If
Next i
Text1.Text = Text1.Text + CStr(num_o) + "个奇数" + vbCrLf
Text1.Text = Text1.Text + "奇数和:" + CStr(sum_o) + vbCrLf
Text2.Text = Text2.Text + CStr(num_e) + "个偶数" + vbCrLf
Text2.Text = Text2.Text + "偶数和:" + CStr(sum_e) + vbCrLf

End Sub

Private Sub Form_Load()
Dim i
Randomize
For i = 0 To 19
num(i) = Int(Rnd * 101)
Next i
End Sub

追问

我需要的是一个C程序...