=(x＋y)(x＋y)²－(x＋y)(x－y)²
=(x＋y)【（x＋y）²－(x－y)²】
=(x＋y)2x2y
=4xy(x＋y)本回答被提问者采纳
=(x+y)(x+y+x-y)(x+y-x+y)
=4xy((x+y)
=(x+y)(x+y+x-y)(x+y-x+y)
=4xy((x+y)
=(x+y)(x+y+x-y)(x+y-x+y)
=4xy((x+y)
(x+y)^3-(x-y)^2(x+y)因式分解
原式为：（x＋y）³－(x－y)²(x＋y)=(x＋y)(x＋y)²－(x＋y)(x－y)²=(x＋y)【（x＋y）²－(x－y)²】=(x＋y)2x2y =4xy(x＋y)
把下列多项式因式分解(x+y)的立方-(x-y)的平方(x+y)
(x+y)^3-(x-y)^2.(x+y)=(x+y)[(x+y)^2-(x-y)^2]=4xy(x+y)
(x+y)^3-(x+y)^2-2(x+y)!因式分解!急急急急急急急急急急急急急急急急...
原式=(x+y)[(x+y)²-(x+y)-2]=(x+y)(x+y+1)(x+y-2)
( (X+Y)^3-(X-Y)^3-(X+Y) )\\(X+Y) 因式分解
( (X+Y)^3-(X-Y)^3-(X+Y) )\\(X+Y)=(X+Y)²-(X-Y)³／(X+Y) -1 =X²＋2XY＋Y²-1-(X-Y)³／(X+Y)怎么会有这样的题呢?是原题吗？
数学因式分解(X+Y )3-(X2-Y2)(X-Y),急求!
(X+Y )3=(x+y)(x2-xy+y2),(x2-y2)(x-y)=(x+y)(x-y)2=(x+y)(x2-2xy+y2),提取(x+y),其余的合并计算结果为xy,所以结果为xy(x+y)。
因式分解:(x+y)^3(x-y)-(x+y)(x-y)^3,
=（x+y)(x-y)[(x+y)^2-(x-y)^2]=(x^2-y^2)[x^2+y^2+2xy-x^2-y^2+2xy] (将大括号的两个算式展开）=4xy(x^2-y^2)希望你能采纳，祝你愉快！
9(x+y)^3-(x-y)^2 因式分解,哪位哥哥姐姐告诉下我啊
错了，第一个也是平方 原式=[3(x+y)]²-(x-y)²=[3(x+y)]+(x-y)][3(x+y)]-(x-y)]=(4x+2y)(2x+4y)=4(2x+y)(x+2y)
(x+y)^3与(x-y)^3的因式分解公式
(x+y)^3=x^3+y^3+3yx^2+3xy^2 (x-y)^3=x^3-y^3-3yx^2+3xy^2 第二个就是y的奇次方项为负
因式分解:(x+y)^3-(x-y)^3
因式分解:(x+y)^3-(x-y)^3解a³-b³=(a-b)(a²+ab+b²) (x+y)³-(x-y)³=[(x+y)-(x-y)][(x+y)²+(x+y)(x-y)+(x-y)²]=2y[x²+2xy+y²+x²-y²+x²+y²-2
因式分解(x+y)^3-(x-y)^3
=[（2x-y）^3-(x-2y)^3]-(x+y)^3 =(2x－y－x＋2y)[(2x－y)²＋(2x－y)(x－2y)＋(x－2y)²]-(x+y)^3 =(x＋y)(7x²－13xy＋7y²)－(x＋y)³=(x＋y)[(7x²－13xy＋7y²)－(x＋y)²]=(x＋y)(6x²－15xy...
