若x^2-|4x 4|与√2x-y-3互为相反数则x y的值是多少？

Answer 1

x^2-|4x+4|=-(2^1/2x-y-3)
当4X+4>0时,两式恒等
x^2-4x-4=-(2^1/2)x+y+3
则x^2=0,-4x=-(2^1/2)x
x=0，y+3=-4 y=-7
当4X+4<0时，两式恒等
x^2+4x+4=-(2^1/2)x+y+3
则x=0, y+3=4 y=1