解方程 【x-1分之2】-【x+1分之3】=x的平方-1分之x+三
同时乘以x的平方-1，变为2（X+1）-3（X-1）=X+3，解得，X=1（不合题意），所以，原方程无解。
X减1分之X减X加1分之3等于1 解方程
x\/(x-1)-3\/(x+1)=1;x(x+1)-3(x-1)=(x+1)(x-1);x²+x-3x+3=x²-1;2x=4;x=2;有帮助请记得好评，新问题请重新发帖提问，谢谢！！！(*^__^*) ……
去分母解方程: (X+1)\/2-(x-1)\/3=1
(X+1)\/2-(x-1)\/3=1 3（x+1)-2(X-1)=6 3x+3-2x+2=6 x=1
x-2\/2 x x-1\/3=1. 解方程
(x-2)\/2 +x +(x-1)\/3=1 两边同乘以6 3(x-2)+6x+2(x-1)=6 3x-6+6x+2x-2=6 11x-8=6 11x=14 x=14\/11
解方程:x-3分之2-x+3-x分之1=1(要检验)
3\/(x-1)-(x+2)\/[x(x-1)]=0 [3x-(x+2)]\/[x(x-1)]=0 [2x-2)]\/[x(x-1)]=0 2\/x=0 无解 (2-x)\/(x-3) + 1\/(3-x) = 1 (2-x)\/(x-3) - 1\/(x-3) = 1 (2-x-1)\/(x-3) = 1 (1-x)\/(x-3) = 1 1-x=x-3 2x=4 x=2 经检验不是增根 ∴x...
解方程x一2分之X一3十1=2一x分之3
答：(x-3)\/(x-2) +1=3\/(2-x)(x-3+x-2) \/(x-2)=-3\/(x-2)(2x-5) \/(x-2)=-3\/(x-2)2x-5=-3 2x=2 x=1 经检验,x=1是原分式方程的根
解方程x减1分之x加2减2x分之1等于3?
x\/(x-1)+1\/(2-2×)=3 x\/(x-1)-1\/2(×-1)=3 2x-1=3×2(×-1)2×-1=6x-6，4x=5，x=5\/4
用换元法解方程(x-1)\/(x+2)-3\/(x-1)-1=0
x-1)]\/(x-1)-1=0 (x-1)\/(x+2)-(x+2)\/(x-1)+1-1=0 (x-1)\/(x+2)-(x+2)\/(x-1)=0 设(x-1)\/(x+2)=y，则y-1\/y=0 即：y²-1=0，解得：y1=1 y2=-1 即：(x-1)\/(x+2)=1，或者(x-1)\/(x+2)=-1 解得：x=-1\/2 经检验是原方程的根 ...
解方程:X-(X-1\/2)=2-(X+2\/3)
X-(X-1\/2)=2-(X+2\/3) X-X+1\/2=2-X-2\/3 两边同乘以6得：6X-6X+3=12-6X-4 6X=5 X=5\/6
解方程:x-1分之2+1-x分之x+2=3的算式
2\/(x-1)+(x+2)\/(1-x)=3 2\/(x-1)-(x+2)\/(x-1)=3 (2-x-2)\/(x-1)=3 -x=3x-3 -x-3x=-3 -4x=-3 x=3\/4
