C语言数组输出一个钻石图形的程序有小问题，在线等啊

Question

#include <stdio.h>
void main(){
char diamond[][5]={{' ',' ','*'},{' ','*',' ','*'},{'*',' ',' ',' ','*'},{' ','*',' ','*'},{' ',' ','*'}}；
int i,j;
for(i=0;i<5;i++){
for(j=0;j<5;j++)
printf("%c",diamond[i][j]);
printf("\n");
}
编译遇到以下错误提示，我查了没看到错哪里啊>
---------- TC 2.0 Build ----------
Turbo C Version 2.01 Copyright (c) 1987, 1988 Borland International
344.c:
Error 344.c 3: Illegal character '? (0xa3) in function main
Error 344.c 3: Illegal character '? (0xbb) in function main
Error 344.c 4: Declaration syntax error in function main
Error 344.c 5: Undefined symbol 'i' in function main
Error 344.c 6: Undefined symbol 'j' in function main
*** 5 errors in Compile ***
Available memory 393840
Output completed (0 sec consumed) - Normal Termination

请指点啊
}

Answer 1

错误有两个：
1.char diamond[][5]={{' ',' ','*'},{' ','*',' ','*'},{'*',' ',' ',' ','*'},{' ','*',' ','*'},{' ',' ','*'}}；这个结束处的分号改成英文的。
2.少一个 “}”。

Answer 2

程序结尾加个大括号就行了。
#include<stdlib.h>
#include <stdio.h>
void main(){
char diamond[][5]={{' ',' ','*'},{' ','*',' ','*'},{'*',' ',' ',' ','*'},{' ','*',' ','*'},{' ',' ','*'}}；
int i,j;
for(i=0;i<5;i++){
for(j=0;j<5;j++)
printf("%c",diamond[i][j]);
printf("\n");
system("pause"):
}
}
换个编译器吧，这错误信息真水。

Answer 3

#include <stdio.h>
void main()
{
int i,j;
char diamond[][5]={{' ',' ','*'},{' ','*',' ','*'},{'*',' ',' ',' ','*'},{' ','*',' ','*'},{' ',' ','*'}};

for(i=0;i<5;i++)
{
for(j=0;j<5;j++)
printf("%c",diamond[i][j]);
printf("\n");
}
}