输入一行字符，分别统计其中英文字母、空格、数字和其它字符个数。

Question

请用循环编写，难了我不懂.....

Answer 1

题目：输入一行字符，分别统计出其中英文字母、空格、数字和其它字符的个数。
1.程序分析：利用while语句,条件为输入的字符不为'\n'.

2.程序源代码：
#include "stdio.h"
main()
{char c;
int letters=0,space=0,digit=0,others=0;
printf("please input some characters\n");
while((c=getchar())!='\n')
{
if(c>='a'&&c<='z'||c>='A'&&c<='Z')
letters++;
else if(c==' ')
space++;
else if(c>='0'&&c<='9')
digit++;
else
others++;
}
printf("all in all:char=%d space=%d digit=%d others=%d\n",letters,
space,digit,others);
}

Answer 2

可以导入一个.txt文件统计其中出现过的字符次数，比如字母a出现了12次

package io.read;
import java.io.*;
import java.util.Enumeration;
import java.util.HashMap;
import java.util.Hashtable;
import java.util.Map;

public class Test {
String filename;
public String read() throws Exception{
//this.filename=filename;
BufferedReader bf=new BufferedReader(
new FileReader(
new File(filename).getAbsoluteFile()));
StringBuffer sb=new StringBuffer();
String s;
while((s=bf.readLine())!=null){
sb.append(s);
sb.append('\n');
}
return sb.toString();
}
public void count(String filename) throws Exception{
this.filename=filename;
String s=read();
//System.out.println(s);
int len=1;
char im;
int sign=0;
char [] c=new char[10240];
int [] in=new int[10240];
//System.out.println(s.length());
for(int i=0;i<s.length();i++){
im=s.charAt(i);
if(im==' '||im=='\n'||im=='\r'||im=='\n'){
continue;
}
for(int j=0;j<len;j++){
if(im==c[j]){
in[j]+=1;
sign=0;
break;
}
sign=1;

}
if(sign==1){
c[len-1]=im;
in[len-1]+=1;
len=len+1;
}

}
for(int i=0;i<len-1;i++){
System.out.print(c[i]+":"+in[i]+" ");
if(i>0&&i%10==0){
System.out.println();
}
}
System.out.println();
System.out.println("总计"+(len-1)+"个字符");
}

public static void main(String[] args) {
Test t=new Test();
try {
t.count("read.txt");
} catch (Exception e) {
//e.printStackTrace();
System.out.println("done");
}

}

}

Answer 3

#include "stdio.h"
main()
{ char *a;
int b[129],i;
scanf ("%s",a);
for (i=0;i<=128;i++)
b[i]=0;
for (i=0;a[i];i++)
b[a[i]]++;
for (i=0;i<=128;i++)
if (b[i]!=0) printf("%c:%d",a[i],b[i]);
}

Answer 4

/***********************************************************************************
第六章随堂练习一
统计字符，单词和行数
**********************************************************************************/
#include<stdio.h>
#include<ctype.h>
#define STOP '|'
int main(void)
{
char c;
char prev;
long n_chars = 0L;
int n_lines = 0;
int n_words = 0;
int p_lines = 0;
int inword = 0;

printf("Enter text to be analyzed( | to be quit):\n ");
prev = '\n';
while((c = getchar()) != STOP)
{
n_chars++;
if (c == '\n')
n_lines++;
if (!isspace(c) && !inword)
{
inword = 1;
n_words++;

}
if(isspace (c) && inword)
inword = 0;
prev = c;
}

if(prev != '\n')
p_lines = 1;
printf("characters = %ld,word = %d,line = %d,",
n_chars,n_words,n_lines);
printf("partial lines = %d\n",p_lines);
return 0;

}