【0.75-（2又1/3-1又1/9）除以4】除以【（1又1/2+2又2/3）除以2又1/2-5/6】

Answer 1

解：
原式=[3/4-（2+1/3-1-1/9)×1/4]÷[(1+1/2+2+2/3）÷5/2-5/6]
=[(3/4-(1+2/9)×1/4]÷[(3+7/6)×2/5-5/6]
=(3/4-11/9×1/4）÷（5/3-5/6）
=4/9÷5/6
=4/9×6/5
=8/15

Answer 2

=[3/4-（2+1/3-1-1/9)×1/4]÷[(1+1/2+2+2/3）÷5/2-5/6]
=[(3/4-(1+2/9)×1/4]÷[(3+7/6)×2/5-5/6]
=(3/4-11/9×1/4）÷（5/3-5/6）
=4/9÷5/6
=4/9×6/5
8分之15