=0.3^-1-(25/4)^1/2+4^3+(1/根号8)^2/3-1/3+1
=10/3-5/2+64+1/2-1/3+1
=3-2+64+1
=66
(0.027)^-1\/3-(6又1\/4)^1\/2+256^3\/4+(2倍根号2)^-2\/3-3^-1+π^0...
(0.027)^-1\/3-(6又1\/4)^1\/2+256^3\/4+(2倍根号2)^-2\/3-3^-1+π^0 =0.3^-1-(25\/4)^1\/2+4^3+(1\/根号8)^2\/3-1\/3+1 =10\/3-5\/2+64+1\/2-1\/3+1 =3-2+64+1 =66
(0.027)^1\/3-(61\/4)1\/2+(2倍根号2)^﹣2\/3-3^﹣1+π^0
(0.027)^1\/3-(61\/4)1\/2+(2倍根号2)^﹣2\/3-3^﹣1+π^0 =0.3-√61\/2+1\/2-1\/3+1 =3\/10+7\/6 -√61\/2 =44\/30-√61\/2 =22\/15-√61\/2
{[0.027)^-1\/3+(1\/6)^-1\/2-(3)^-1]除以[(-10)^0-(3)^-1]} *((3-0.7...
5 约分后得72\/7 6 约分后得31\/60 7 约分后得3\/4 1 两边同除以5 得3\/19 2 两边同乘以21\/8 得7\/10 3 两边同乘以5\/4 得75\/112 4 两边同乘以4，再乘以3\/2 得72赞同2
0.027^(-1\/3)-(-1\/6)^(-2)+256^(0.75)-(四又17\/27)^(-1\/3)+5\/9^...
0.027^(-1\/3)-(-1\/6)^(-2)+256^(0.75)-(四又17\/27)^(-1\/3)+5\/9^(-1)-729^-(1\/6)=10\/3-36＋64-3\/5＋9\/5-1\/3 =10\/3-1\/3＋【64-36】＋【9\/5-3\/5】=3＋28＋6\/5 =32又1\/5
(0.027)^-1\/3+(√2√2)^4\/3-4*(16\/49)^-1\/2-4^√2*8^0.25+(-2014)^0=...
(0.027)^-1\/3+(√2√2)^4\/3-4*（16\/49）^-1\/2-4^√2*8^0.25+(-2014)^0=(0.3^3)^(-1\/3)+[2^(3\/4)]^4\/3-4*[(4\/7)^2]^(-1\/2)-4^√2*2^(3\/4)+1=1\/0.3+2-7+1-4^√2*2^(3\/4)=22\/3-4^√2*2^(3\/4)
0.027^(—1\/3)—【—(1\/6)】^(—2) 256^0.75—3^(—1) (√(1\/2))^0
原式=10\/3-1\/36+64-1\/3+1 =67又35\/36。
化简1)【(0.027)的-1\/3次方+(1\/6)的-2次方-3的-1次方】\/【(10)的0次 ...
答案：-0.02
(0.027)的三分之一次方–(–十分之一)²+256¾-3的负一次方+1
(0.027)的三分之一次方–(–十分之一)²+256¾-3的负一次方+1 =0.3-0.01+64-1\/3+1 =（64+1）+（0.3-0.01-1\/3）=65-13\/300 =64又287\/300
1.计算) 0.027^(-1\/3)-(-1\/(81))^0-1?
原式＝1／0.027＾（1／3）-1-1 ＝1／0.3-2 ＝10／3-2 ＝4／3
如图,实数指数幂计算题(0.027)^(-1\/3)-(-1\/7)^(-2)……等于多少?
解：原式=[(0.3)^3]^(-1\/3)-[(-7^(-1)]^(-2)+√(25\/9)-1=(0.3)^(-1)-(-7)^2+5\/3-1=10\/3-49+5\/3-1 =-45
