求大侠用c++编写一个程序，要求输入十个学生的姓名，学号和成绩，并输出不及格的姓名，学号和成绩

Answer 1

//用结构体做
#include <iostream>
using namespace std;
#include <string>

struct Student{
string name;
int ID;
int score;
}stu[10];

int main()
{
int n = 10;
int i;
for(i = 0; i < n; ++i)
{
cout<<"输入第"<<i+1<<"位同学的名字：\n";
cin>>stu[i].name;
cout<<"学号：";
cin>>stu[i].ID;
cout<<"成绩：";
cin>>stu[i].score;
}
cout<<"不及格的同学有：\n";
cout<<"名字\t学号\t成绩\n";
for(i = 0; i < 10; ++i)
if(stu[i].score < 60)
cout<<stu[i].name<<"\t"<<stu[i].ID<<"\t"<<stu[i].score<<endl;
return 0;
}

Answer 2

#include<stdio.h>

struct student
{
int stuNo;
char stuName[10];
float grade;
};
int main()
{
student stu[10];
int i;
printf("please input 10 student information:\n");
for(i=0;i<10;i++)
{
printf("the number %d:\n",i+1);
printf("name:");
scanf("%s",&stu[i].stuName);
printf("stuNo:");
scanf("%d",&stu[i].stuNo);
printf("Grade:");
scanf("%f",&stu[i].grade);
}
for(i=0;i<10;i++)
{
if(stu[i].grade<60)
printf("\nName:%s\nstuNo:%d\nGrade:%f",stu[i].stuName,stu[i].stuNo,stu[i].grade);
}
return 0;
}

Answer 3

这个很简单啊