=1-1/64
=63/64追问
解释一下吧，我才四年级，不懂
追答你画个图，就很容易看出来了
1/2+1/4+1/8+1/16+1/32+1/64
=1/2+1/4+1/8+1/16+1/32+1/64+1/64-1/64
=1-1/64
=63/64
1/2+1/4+1/8+1/16+1/32+1/64+1/64=1
=1/2+1/4+1/8+1/16+1/32+1/32-1/32
=1-1/32
=31/32
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64的简便运算
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/64-1\/64 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/32-1\/64 =1\/2+1\/4+1\/8+1\/16+1\/16-1\/64 =1\/2+1\/4+1\/8+1\/8-1\/64 =1\/2+1\/4+1\/4-1\/64 =1\/2+1\/2-1\/64 =1-1\/64 =63\/64 希望帮到...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64的简便方法。
拼凑法：原式=（（1\/2 + 1\/4 + 1\/8 + 1\/16 + 1\/32 + 1\/64） + 1\/64） -1\/64 =（1\/2 + 1\/4 + 1\/8 + 1\/16 + 1\/32 + 1\/32） -1\/64 =（1\/2 + 1\/4 + 1\/8 + 1\/16 + 1\/16） -1\/64 =（1\/2 + 1\/4 + 1\/8 + 1\/8） -1\/64 =（1\/2 + 1\/4 ...
1\/2+1\/4+1\/8,加1\/16+1\/32+1\/64简便计算?
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =1\/2+1\/4+1\/8+1\/16+1\/32+(1\/64+1\/64)-1\/64 =1\/2+1\/4+1\/8+1\/16+(1\/32+1\/32)-1\/64 =1\/2+1\/4+1\/8+(1\/16+1\/16)-1\/64 =1\/2+1\/4+(1\/8+1\/8)-1\/64 =1\/2+(1\/4+1\/4)-1\/64 =1\/2+1\/2-1\/64 =1-1\/64 =6...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64简便计算的方法和思路?
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =（4\/8+2\/8+1\/8）+（4\/64+2\/64+1\/64）=7\/8+7\/64 =56\/64+7\/64 =63\/64 存疑请追问，满意请采纳
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64等于多少
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64等于63\/64 使用简便计算即可，计算过程如下：1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/64-1\/64 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/32-1\/64 =1\/2+1\/4+1\/8+1\/16+1\/16-1\/64 =1\/2+1\/4+1\/8+1\/8-1\/...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64简便计算的方法和思路?
假设：s=1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 ；则：2s=1+1\/2+1\/4+1\/16+1\/32 ；用2s-s(相同项全部抵消,只剩首位2项) ；s=1-1\/64=63\/64。1．分式加减法法则：（1）通分：把异分母的分式化为同分母分式的过程，叫做通分。（2）同分母分式的加减法法则：同分母的分式相加减，分母不...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128等多少?简便计算
加第四项等于15\/16。第一项加第二项加第三项加第四项加第五项等于31\/32。从中可以发现他的答案就是分子比分母少一，∴然后加起来的答案就是127\/128。如果是高中的话，那么这道题就是一个等比数列。它的公比为1\/2。所以可根据公式1-q分之a1(1-q的n)∴最后的答案也是127\/128。
1\/2加1\/4加1\/8加1\/16加1\/32加1\/64的简便计算
63\/64 因为每一项后面的分母都是前面的一半，所以你可以在原来的式子最后+1\/64，可以发现从后往前算，就是2个1\/64加起来变成1个1\/32，然后2个1\/32加起来变成1个1\/16，依次类推，。。。最后就是2个1\/2加起来变成1。所以你其实只要将1-1\/64=63\/64即可。此法可推广到更多项 ...
1\/64+1\/32+1\/16+1\/8+1\/4怎么简算?
方法一：1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =1-1\/64 =63\/64 方法二 1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =(1\/2+1\/4+1\/8+1\/16+1\/32+1\/64)-1\/64 =1-1\/64 =63\/64 方法三 令S=1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 2S=1+1\/2+1\/4+1\/8+1\/16+1\/32 S=2S-S=1-1...
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64=
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64等于63\/64 具体解法如下：1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =32\/64+16\/64+8\/64+4\/64+2\/64+1\/64 =（32+16+8+4+2+1）\/64 =63\/64
