...2\/(x+3)+3\/2=7\/2x+6 1-x\/(x-2)+2=1\/(2-x) 求过程
x+4x-2x=4+2 3x=6 x=2 检验:把x=2代入x²-4=2²-4=0 所以 x=2是原方程的增根,原方程无解 2\/(x+3)+3\/2=7\/(2x+6)2\/(x+3)+3\/2=7\/[2(x+3)] 方程两边同时乘最简公分母2(x+3)4+3(x+3)=7 4+3x+9=7 3x=7-4-9 3x=-6 x=-2 检验:把x=-2...
解分式方程1\/x(x+2)+1\/(x+2)(x+4)+1\/(x+4)(x+6)=3\/2(x+6)
2\/x=(3x+10)\/2(x+6)3x²+10x=4x+24 3x²+6x-24=0 x²+2x-8=0 (x+4)(x-2)=0 ∴x=-4 x=2 检验:x=-4是增根 ∴方程的解是x=2
...求值:1\/x+2-(x²-4x+4\/x²-x)除以(x+1-3\/x-1)
原式=1\/(x+2) - (x²-4x+4)\/(x²-x) ÷ [ x+1 -3\/(x-1) ]=1\/(x+2) -(x-2)²\/[x(x-1)] ÷[ (x+1)(x-1)\/(x-1) -3\/(x-1) ]=1\/(x+2) -(x-2)²\/[x(x-1)] ÷(x²-1-3)\/(x-1)=1\/(x+2) -(x-2)²\/[...
计算:1\/(x+2)+(x+6)\/(x^2-4)-(2x+1)\/(x^2-4x+4)
1\/(x+2) +(x+6)\/(x²-4) -(2x+1)\/(x²-4x+4)=1\/(x+2) +(x+6)\/[(x+2)(x-2)] -(2x+1)\/(x-2)²=[(x-2)²+(x+6)(x-2)-(2x+1)(x+2)]\/[(x+2)(x-2)²]=(x²-4x+4+x²+4x-12-2x²-5x-2)\/[(x+2...
去分母解方程1\/(x+2)+4x\/(x^2-4)+2\/(2-x)=1产生的增根是多少?
1\/(x+2)+4x\/(x^2-4)+2\/(2-x)=1 1\/(x+2)+4x\/(x+2)(x-2)-2\/(x-2)=1 x-2+4x-2x-4=x²-4 x²-3x+2=0 (x-1)(x-2)=0 x=1,x=2 增根是x=±2
解方程:(1\/x+2)+(4x\/x的平方-4)+(2\/2-x)=1
(1\/x+2)+(4x\/x的平方-4)+(2\/2-x)=1 两边乘(x+2)(x-2)x-2+4x-2(x+2)=(x+2)(x-2)x-2+4x-2x-4=x^2-4 3x-6=x^2-4 x^2-3x+2=0 (x-2)(x-1)=0 x1=2 x2=-1 由于x≠2 所以x=-1
解方程:1\/(x+2)+1\/(x-2)=1 3x\/(x²-1)+(x²-1)\/3x=5\/2
1)两边同时乘以(x+2)(x-2)x-2+x+2=x^2-4 x^2-2x-4=0 x=1±√5 经检验,它们都是原方程的根 2) 令t=3x\/(x^2-1)方程化为t+1\/t=5\/2 t^2+5t\/2+1=0 (t+2)(t+1\/2)=0 t=-2, -1\/2 当t=-2时,3x\/(x^2-1)=-2, 得2x^2+3x-2=0, (2x-1)(x+...
x\/(x+2)+(x+6)\/(4-x^2)=2x\/(x+2)-1
x\/(x+2)-(x+6)\/(x+2)(x-2)=2x\/(x+2)-1 x(x-2)-(x+6)=2x(x-2)-(x+2)(x-2)x²-2x-x-6=2x²-4x-x²+4 x=10 经检验:x=10是方程的解 ∴方程的解是x=10
化简:1. x²\/(x-2)-4x\/(x-2)+4\/x-2 解方程:1. x\/(x-1)-2\/x=1
=(x+2)2.解方程:x\/(x-1)-2\/x=1 通分得:x²-2(x-1)=x(x-1)展开得:x²-2x+2=x²-x 化简得:x=2 经检验,x=2为原方程的解。3.(a+(1)\/a-2)÷(a²+a-2)\/(a²-4)=[(a²-2a+1)(a²-4)]\/[(a-2)(a+2)(a-1...
1.先化简,再求代数式 (1-4\/(x+2))(x^2-4x+4
[1-4\/(x-2)]×(x²-4x+4)=[1-4\/(x-2)]×(x-2)²=(x-2)²-4(x-2)不知道你这个题目后面什么内容,麻烦你查一下原题。