1又1/2+2又1/6+3又1/12+4又1/20+5又1/30=？（简便方法，写过程）

Answer 1

提取前面的整数
：1+2+3。。。+10＝55
分数部分：
1/2=1-1/2
1/6=1/2-1/3
1/12=1/3-1/4
.
.
.
1/110=1/10-1/11
加起来为1-1/11=10/11
所以得数为55又10/11

Answer 2

1又1/2+2又1/6+3又1/12+4又1/20+5又1/30
=(1+2+3+4+5)+(1/2+1/6+1/12+1/20+1/30)
=5*6/2+((1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6))
=15+(1-1/6)
=15+5/6
=95/6

Answer 3

15又5/6
先加1+2+3+4+5
再把1/2，1/6等等通分成六十分之几的形式
等于50/60
当然用计算器更简便

Answer 4

原式=1+2+3+4+5)+(1/2+1/6+1/12+1/20+1/30)
=15+[(1-1/2)+(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)]
=15+(1-1/6)
=15+5/6
=95/6

Answer 5

3/2+(11/3-3/2)+(27/4-11/3)+(54/5-27/4)+(95/6-54/5)
=95/6