C#编程，根据一元二次方程 的求根公式 ，编写程序求解一元二次方程组的解

Question

只要C#的
根据一元二次方程的求根公式 ，编写程序求解一元二次方程组的解，只考虑实数解，要求区分两根不同和两根相等两种情况考虑，若两根相同则在控制台输出“x1=x2=****”，若两个不相同则输出“x1=****, x2=****”
不是C#a...

Answer 1

static void Main(string[] args)
{
Double A;
Double B;
Double C;
Double T;
Double X1;
Double X2;
Console.WriteLine("请输入3个数");
try
{
A = Double.Parse(Console.ReadLine());
B = Double.Parse(Console.ReadLine());
C = Double.Parse(Console.ReadLine());

if (A == 0)
{
Console.WriteLine("不是一元二次方程");
Console.ReadLine();
}
else
{
T = B * B - (4 * A * C);
if (T > 0)
{
X1 = ((-B) + Math.Sqrt(T)) / (2 * A);
X2 = ((-B) - Math.Sqrt(T)) / (2 * A);
Console.WriteLine(X1);
Console.WriteLine(X2);
Console.ReadLine();
}
if (T < 0)
{
X1 = (-B) / (2 * A);
X2 = Math.Sqrt((-T)) / (2 * A);
Console.WriteLine("X1 = {0} + {1}i", X1, X2);
Console.WriteLine("X2 = {0} - {1}i", X1, X2);
Console.ReadLine();
}
if (T == 0)
{
X1 = X2 = (-B) / (2 * A);
Console.WriteLine(X1);
Console.WriteLine(X2);
Console.ReadLine();
}
}
}
catch (Exception ex)
{
Console.WriteLine(ex.Message);
Console.ReadLine();
}
}

Answer 2

#includ<math.h>
void main( )
{flot a,b,c,d,x1,x2;
scanf("%f,%f,%f",&a,&b,&c);
d=b*b-4*a*c;
x1=(-b+sprq(d))/(2*a);

Answer 3

#include <iostream>
#include <math.h>
using namespace std;
int main()
{float a,b,c,disc;
cout<<"please input a,b,c:";
cin>>a>>b>>c;
if (a==0)
cerr<<"a is equal to zero,error!"<<endl;
else
if ((disc=b*b-4*a*c)<0)
cerr<<"disc=b*b-4*a*c<0"<<endl;
else
if((disc=b*b-4*a*c)>0)
cout<<"x1="<<(-b+sqrt(disc))/(2*a)<<endl;
cout<<"x2="<<(-b-sqrt(disc))/(2*a)<<endl;
if((disc=b*b-4*a*c)=0)
cout<<"x1=x2="<<(-b+sqrt(disc))/(2*a)<<endl;
return 0;
}