汇编语言 实现从键盘上接收两个一位十六进制数据,求其和,并以十进制形式显示出来.

Answer 1

DATAS SEGMENT
buf db 0ah,0dh,?,?,?,'$'
DATAS ENDS

STACKS SEGMENT
dw 10 dup(0)
STACKS ENDS

CODES SEGMENT
ASSUME CS:CODES,DS:DATAS,SS:STACKS
START:
MOV AX,DATAS
MOV DS,AX

mov cx,2
lea si,buf+2
a4: mov ah,1
int 21h
cmp al,'9'
ja a1
sub al,30h
jmp a2
a1:cmp al,'Z'
ja a3
sub al,37h
jmp a2
a3:sub al,57h
a2:mov [si],al
inc si
dec cx
jnz a4
;输入十六进制数字，大小写随意
mov al,buf+2
add al,buf+3
;加法
mov bl,100
cbw
div bl
add al,30h
mov buf+2,al
;十进制百位
mov al,ah
mov bl,10
cbw
div bl
add al,30h
mov buf+3,al
add ah,30h
mov buf+4,ah
;十进制十位、个位
lea dx,buf
mov ah,9
int 21h
;显示
MOV AH,4CH
INT 21H
CODES ENDS
END START

Answer 2

;只能用大写字母数字，测试通过
ASSUME CS:CODES,DS:DATAS,SS:STACKS

DATAS SEGMENT
buf db 0ah,0dh,?,?,0ah,0dh,'$'
DATAS ENDS

STACKS SEGMENT
dw 10 dup(0)
STACKS ENDS

CODES SEGMENT

START:
MOV AX,DATAS
MOV DS,AX

mov ah,1
int 21h
xor ah,ah

a1: cmp al,'A'
jae a2
sub al,30h
jmp a3
a2: sub al,37h

a3: lea si,buf
mov [si+2],al

mov ah,1
int 21h
xor ah,ah

a4: cmp al,'A'
jae a5
sub al,30h
jmp a6
a5: sub al,37h

a6: add al,[si+2]
xor ah,ah
cmp al,9
jna a7
mov bl,10
div bl
xchg al,ah
a7: add ax,3030h
mov [si+2],ah
mov [si+3],al

lea dx,buf
mov ah,9
int 21h

; jmp START ;测试用

ret
CODES ENDS

Answer 3

mov cx,2
lea si,buf+2
a4: mov ah,1
int 21h
cmp al,'9'
ja a1
sub al,30h
jmp a2
a1:cmp al,'Z'
ja a3
sub al,37h
jmp a2
a3:sub al,57h
a2:mov [si],al
inc si
dec cx
jnz a4
;输入十六进制数字，大小写随意
mov al,buf+2
add al,buf+3
;加法
mov bl,100
cbw
div bl
add al,30h
mov buf+2,al
;十进制百位
mov al,ah
mov bl,10
cbw
div bl
add al,30h
mov buf+3,al
add ah,30h
mov buf+4,ah
;十进制十位、个位
lea dx,buf
mov ah,9
int 21h
;显示
MOV AH,4CH
INT 21H
CODES ENDS
END START