解不等式组 x-3(x-2)≥4,2x-1\/5<x+1\/2
解不等式①得:x≤1 解不等式②得:x<-7 所以不等式组的解集为x<-7
解不等式组x-3(x-2)≥4 2x-1\/5>x+1\/2要过程
由x-3(x-2)≥4得,x-3x+6≥4,-2x≥-2,x≤1 由2x- 1\/5>x+ 1\/2 得,x>7\/10 综上可得, 7\/10<x≤1
解不等式:x-3(x-2)≥4,2x-1\/5<x+1\/2求大神帮助
x-3(x-2)>=4 2x>=2 x>=1 2x -1\/5<x+1\/2 x<1\/2+1\/5 x<7\/10
x-3(x-2)≥4,①5分之2x-1<二分之x+1②解不等式组
解:x-3(x-2)≥4,① (2x-1)\/5<(x+1)\/2② x-3x+6≥4 两边同时乘以10,得 4x-2<5x+5 -2x≥4-6 4x-5x<5+2 -2x≥-2 -x<7 x≤1 x>-7 ∴不等式组的解集为:-7<x≤1 确定不等式解集的口诀:大大取大:小小取小:大小小大中间找:大大小小无解了...
x-3(x-2)≥4,2x-1\/5>x+1\/2解方程组
x-3(x-2)≥4 x-3x+6≥4 2x≤2 x≤1 2x-1\/5>x+1\/2 两边乘10 2(2x-1)>5(x+1)4x-2>5x+1 x<-3 所以x<-3
不等式组{x-3(x-2)≥4 5分之2x-1>2分之x+1
整理不等式组得:{-2x+6≥4① {4x-2>5x+5② 解不等式①得:x≤1 解不等式②得:x<-7 所以不等式的解集为x<-7
解下列不等式:(1){x-3(x-2)≥4,2x-1\/5>x-1\/2 。(2 ) {1-3(x-1)<6...
(1){x-3\/10 -3\/10<x<=2 (2){x>-1 ;x属于R x>-1
解不等式组x-3(x-2)大于等于4 5分之2x-1小于2分之x-1
解 x-3(x-2)>4 x-3x+6>4 -2x>-2 x
帮我解解:解不等式组x-3(x-2)大于等于4,3分之1+2x大于x-1
X-3(X-2)大于等于4 原式得-3(X-2)≥4-X -3X+6≥4-X 2X≤-4 X≤-2 1\/3+2X>X-1 2X>X-1-1\/3 X>-1-1\/3 X>-4\/3 补充: 不理解请追问,理解了请点下右下方的“采纳答案” 3Q^-^!予人玫瑰,手有余香 !求采纳 ...
x-3(x-2)≥4 2x-1\/5>x+1\/2 (要详细过程)
2011-07-09 解不等式组x-3(x-2)≥4 2x-1\/5>x+1\/2 2014-06-29 解不等式:x-3(x-2)≥4,2x-1\/5<x+1\/2求大... 2012-05-12 x-3(x-2)小于等于4 2x-1\/5>x+1\/2 12 2012-05-21 2.解下列不等式祖:(4)x-3(X-2)≥4 (5)X-3... 4 2013-05-08 3x-5\/x-2=2-x+1\/x...