=（1-1/2）+（1/2-1/4)+(1/4-1/8)+(1/8-1/16)+...+(1/128-1/256)
=1-1/2+1/2-1/4++1/4-1/8+1/8-1/16+1/16-.-1/128+1/128-1/256
=1-1/256
=255/256
本题是分数加减法的简便运算题，主要利用各个数之间的特殊关系，将各个数用”拆项法“拆开，如;将1/2拆成1-1/2，1/4 拆成1/2-1/4,从而形成一加一减的运算方式，来达到简算的目的。
=(1/2+1/4)+1/8+1/16+......+1/256
=3/4+1/8+1/16+......+1/256
=(3/4+1/8)+1/16+......+1/256
=7/8+1/16+......+1/256
=......
=127/128+1/256
=255/256本回答被提问者和网友采纳
=（1-1/2）+（1/2-1/4)+(1/4-1/8)+(1/8-1/16).+(1/128-1/256)
=1-1/2+1/2-1/4++1/4-1/8+1/8-1/16+1/16-.-1/128+1/128-1/256
=1-1/256
=255/256
简算1\/2+1\/4+1\/8+...+1\/256?
这是等比数列前8项的和，用等比数列求和公式就可以了，首项是1\/2, 公比是1\/2，结果是1\/2乘以(1-1\/2的8次方)\/(1-1\/2)=1-1\/256=255\/256.
1\/2+1\/4+1\/8+1\/16+……+1\/256=?
1\/2＋1\/4＋1\/8＋1\/16＋1\/32＋?＋1\/256＝255\/256。解：1\/2+1\/4+1\/8+1\/16＋1\/32＋?＋1\/256 =1\/2+1\/2^2+1\/2^3+1\/2^4+1\/2^5+...+1\/2^8 =1\/2*(1-(1\/2)^8)\/(1-1\/2)=255\/256
1\/2+1\/4+1\/8+1\/16= 用简便方法计算?
用简便方法计算就是把算式变成8\/16+4\/16+2\/16+1\/16=15\/16。用通分的方式计算比较容易简便。
...之一+十六分之一+三十二分之一……+128分之1+256分之1
简单啊 S=1\/2+1\/4+1\/8+1\/16+...+1\/128+1\/256 两边同时乘以1\/2得 (1\/2)S=1\/4+1\/8+1\/16+...+1\/128+1\/256+1\/512 好了，上面两个式子，左边减左边，右边减右边 得S-(1\/2)S=1\/2-1\/512 即(1\/2)S=1\/2-1\/512 所以S=1-1\/256=255\/256 ...
1\/2+1\/4+1\/8+...+1\/256=? 要算式的哈
解： 1\/2+1\/4+1\/8+...+1\/256 =1-1\/256 =255\/256
1\/2+1\/4+1\/8一直加到1\/256,它们的和是多少?
简便计算 1\/2+1\/4+1\/8+...+1\/256 =1-1\/2+1\/2-1\/4+1\/4-1\/8+...+1\/128-1\/256 =1-1\/256 =255\/256
1\/2+1\/4加1\/8+1\/16等于多少
方法一：1\/2+1\/4加1\/8+1\/16 =8\/16+4\/16+2\/16+1\/16 =15\/16 方法二：1\/2+1\/4加1\/8+1\/16 =1-1\/2+1\/2-1\/4+1\/4-1\/8+1\/8-1\/16 =1-1\/16 =15\/16
1\/2+1\/4+1\/8+1\/32+1\/64+1\/128+1\/256
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64+1\/128+1\/256 =1\/2+（1\/2-1\/4）+（1\/4-1\/8）+（1\/8-1\/16）……（1\/128-1\/256）=1-1\/256 =255\/256
1\/2+1\/4+1\/8+1\/16+1\/32+1\/64简便计算的方法和思路?
简便计算1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 解题思路：四则运算规则（按顺序计算、先算乘除后算加减，有括号先算括号，有乘方先算乘方）即脱式运算（递等式计算）需在该原则前提下进行 解题过程：1\/2+1\/4+1\/8+1\/16+1\/32+1\/64 =（4\/8+2\/8+1\/8）+（4\/64+2\/64+1\/64）=7\/8+7\/...
1\/2+1\/4+1\/8+1\/16+1\/32 用简便方法算
1\/2+1\/4+1\/8+1\/16+1\/32 =1\/2+1\/4+1\/8+1\/16+1\/32+1\/32-1\/32 =1\/2+1\/4+1\/8+1\/16+1\/16-1\/32 =1\/2+1\/4+1\/8+1\/8-1\/32 =1\/2+1\/2-1\/32 =1-1\/32 =31\/32
