C++高手请进帮忙写个代码，十万火急！！！

Question

###注意：请运行程序无错误后再给我答案，这是个很重要的作业，谢谢。。。以下是题目：
1.Write a program that stores and prints ONE HUNDRED (100) integers in a 2D (twodimensional)
array of TEN (10) rows and TEN (10) columns. Fill the array with random integers
in between 1 to 100. Calculate how many odd values and even values are there in the array. Note
that the random integers should very be varied every time the program is run.

Answer 1

// sgjv.cpp : Defines the entry point for the console application.
//
// 1.Write a program that stores and prints ONE HUNDRED (100) integers in a 2D (twodimensional)
// array of TEN (10) rows and TEN (10) columns. Fill the array with random integers
// in between 1 to 100. Calculate how many odd values and even values are there in the array. Note
// that the random integers should very be varied every time the program is run.
#include "stdafx.h"
#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <time.h>
using namespace std;
int main(void)
{
int iarray[10][10];
int i,j;
int odd=0,even=0;
srand(time(NULL)); // 去当前时间做种子
for (i=0;i<10;i++)
{
for (j=0;j<10;j++)
{
iarray[i][j] = rand()%99+1;
}
}
for (i=0;i<10;i++)
{
for (j=0;j<10;j++)
{
if (iarray[i][j]%2 == 0)
{
even++;
}
else
{
odd++;
}

}
}
for (i=0;i<10;i++)
{
for (j=0;j<10;j++)
{
cout.width(5); //设置输出宽度5
cout.setf(ios::left); //设置左对齐输出
cout<<iarray[i][j];
}
cout<<endl;
}
cout<<"odd NO::"<<odd<<endl; //输出奇数个数
cout<<"even NO::"<<even<<endl;// 输出偶数个数
return 0;
}

Answer 2

兄弟给分哦!
VC6下跑莫问题！
#include "iostream.h"
#include "time.h"
#include "stdlib.h"

#define MAX_ROW 10
#define MAX_LINE 10

/*!
this function will set seed by system time to
generate different number.
*/
void setSeed()
{
srand((unsigned)time(NULL));
}

/*!
this function will create random array integer.
\return bool false(operate failure)|true(successful)
*/
bool createRandom(int (*pParam)[MAX_LINE])
{
if (!pParam)
{
cout << "input pointer is null" << endl;
return false;
}

setSeed();

for(int i = 0; i < MAX_ROW; i++)
{
for(int j = 0; j < MAX_LINE; j++)
{
pParam[i][j] = rand()%100 + 1;
}
}

return true;

}

/*!
entrance of application.
*/
int main(int argc, char **argv)
{
int arrayNum[MAX_ROW][MAX_LINE] = {0};

cout << "----------------create random------------------"<<endl;
if(!createRandom(arrayNum))
{
cout << "create random failure!\n" << __LINE__ << endl;
return -1;
}
cout << "----------------create succesful------------------" << endl;

int iRet = 0;

cout << "display random array:\n";
for(int i = 0; i < MAX_ROW ; i++)
{
for(int j = 0; j < MAX_LINE; j++)
{
arrayNum[i][j]%2 ? iRet++ : 0;
cout << arrayNum[i][j] << " " ;
}

cout << endl;
}

cout << "the number of odd in array is :" << iRet <<endl;

return 0;
}

Answer 3

这么简单的题目，还是自己完成比较好

Answer 4

自己写

Answer 5

像这样简单的问题都不自己动手做？