输入一组同学的分数,以负值作为结束符,输出其中的最大值和平均值 c语言 输

Question

快点等不及了

Answer 1

#include<stdio.h>
void main()
{
int num,i,j;
float a[100],b[100],sum=0,ave;
printf("请输入一组同学的成绩并以负值结束：\n");
for(;a[i]>=0;i++)
{
scanf("%f",a[i]);
sum=sum+a[i];
b[j++]=a[i];
num++;
}
for(j=0;j<num;j++)
{
for(i=j+1;i<num-1;i++)
{
int tem;
if(b[j]<b[i])
{
tem=b[j];
b[j]=b[i];
b[i]=tem;
}
}
}
ave=sum/num;
printf("平均值是：%f",&ave);
printf("最大值是：%f",b[0]);
}
//差不多就是这样吧！你自己看看C语言书调试一下，上了两年都快忘光了，仅作参考，见笑啦！

Answer 2

因为不知道具体人数，所以没法用数组，现用结构体类型，希望你能够看懂：
#include<stdio.h>
#include<malloc.h>
#include<conio.h>
struct student
{
double score;
struct student *next;
};
main()
{
struct student *head,*tail,*p;
double num,sum,t,a,c;
head=tail=NULL;
printf("请输入成绩并以负数结束：\n");
scanf("%lf",&num);
while(num>0.0)
{p=(struct student *)malloc(sizeof(struct student));
p->score=num;
if(head==NULL)
head=p;
else
tail->next=p;
tail=p;
scanf("%lf",&num);
}
tail->next=NULL;
p=head;
if(p!=NULL)
a=p->score;
while(p->next!=NULL)
{
p=p->next;
c=a;
sum=sum+c;
c=p->score;
if(a>p->score)
{ t=p->score;
p->score=a;
a=t;}
a=p->score;
}
sum=sum+a;
printf("其和为:%.2lf\n",sum);
printf("最大值为：%.2lf",a);
getch();
}