第1个回答 推荐于2017-09-04
令t=1/x,原极限=limx-->0[ ( (a1)^t+(a2)^t+(a3)^t+…+(an)^t)/n]^n/t =exp{limx-->0 (n/t)ln[ ( (a1)^t+(a2)^t+(a3)^t+…+(an)^t)/n]} 应用诺必达=exp{limx-->0n[((a1)^t ln(a1)+(a2)^t ln(a2)+…+(an)^t ln(an))/((a1)^t+(a2)^t+…+(an)^t)]} ∵limx-->0(ai)^t=1;∴原极限=exp{ln(a1)+ln(a2)+ln(a3)+...ln(an)} =(a1)(a2)(a3)...(an) 纯手打,本回答被网友采纳