=(1/6)sin6x+C
求不定积分∫cos6x dx
回答：∫cos6x dx =1\/6∫cos6x d6x =1\/6∫ dsin6x =sin6x \/ 6 +C
求不定积分∫cos6x dx
∫cos6x dx =1\/6∫cos6x d6x =1\/6∫ dsin6x =sin6x \/ 6 +C
不定积分求解:∫cos^6(x)dx
如上图所示。
求不定积分∫sin^3x\/cos^6xdx
简单分析一下，详情如图所示
求不定积分∫cos(2x+6)dx
∫cos6x dx =1\/6∫cos6x d6x =1\/6∫ dsin6x =sin6x \/ 6 +C
cosx^6的不定积分
∫ dx + (15\/32)∫cos2x dx + (3\/16)∫cos4x dx + (1\/32)∫cos6x dx = (5\/16)∫ dx + (15\/32)(1\/2)∫cos2x d(2x) + (3\/16)(1\/4)∫cos4x d(4x) + (1\/32)(1\/6)∫cos6x d(6x)= (5\/16)x + (15\/64)sin2x + (3\/64)sin4x + (1\/192)sin6x + C ...
关于不定积分和定积分
=cos^5xsinx|(0,π\/2)+∫(0,π\/2) 5sin^2xcos^4xdx =∫(0,π\/2) 5(1-cos^2x)cos^4xdx =5∫(0,π\/2) cos^4xdx-5∫(0,π\/2) cos^6xdx ∫(0,π\/2) cos^6xdx=(5\/6)*∫(0,π\/2) cos^4xdx =(5\/6)*(3\/4)*∫(0,π\/2) cos^2xdx =(5\/6)*(3\/4)*(1...
cos(3x)的平方的不定积分在线等
三角函数性质：cos²x = (1 + cos2x)\/2 ∫ cos²(3x) dx = ∫ (1 + cos6x)\/2 dx = (1\/2)∫ dx + (1\/2)∫ cos6x dx = (1\/2)∫ dx + (1\/2)(1\/6)∫ cos6x d(6x)= (1\/2)x + (1\/12)sin6x + constant ...
求解一道不定积分高数题。∫cos^6x\/sin^2x dx =?附上图片,不知道我这样...
回答：arctan(tanx)=x
求不定积分(cosx)^6dx
楼上的答案经过数学软件验算，答案错误。其原函数的导数是cos^6x + 3\/16正确答案如图：
