|1/3-1/2|+|1/4-1/3|+|1/5-1/4|+|1/6-1/5|+|1/7-1/6|+|1/8-1/7|+|1/9-1/8|+1/10-1/9|=

我需要解题的过程!谢谢!

解:
由题可知
1/3-1/2<0
1/4-1/3<0
1/5-1/4<0
……
1/10-1/9<0
所以原式=-(1/3-1/2)-(1/4-1/3)-(1/5-1/4)-……-(1/10-1/9)
=1/2-1/3+1/3-1/4+1/4-1/5+……+1/9-1/10
=1/2-1/10
=2/5
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第1个回答  2008-09-09
直接去掉绝对值符号,很多项就互相抵消了
结果是2/5

|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|+|...
解:由题可知 1\/3-1\/2<0 1\/4-1\/3<0 1\/5-1\/4<0 ……1\/10-1\/9<0 所以原式=-(1\/3-1\/2)-(1\/4-1\/3)-(1\/5-1\/4)-……-(1\/10-1\/9)=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10 =2\/5 ...

|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|1\/...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|1\/9-1\/8|+1\/10-1\/9│ =1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7+1\/7-1\/8+1\/8-1\/9+1\/9-1\/10 =1\/2-1\/10 =2\/5 ...

1+1\/3-1\/2+1\/4-1\/3+1\/5-1\/4+1\/6-1\/5+1\/7-1\/6+1\/8-1\/7+1\/9-1\/8+1\/1...
原式 = 1 + 1\/3 + 1\/4 + 1\/5 + 1\/6 + 1\/7 + 1\/8 + 1\/9 + 1\/10 - 1\/2 - 1\/3 - 1\/4 - 1\/5 - 1\/6 - 1\/7 - 1\/8 - 1\/9 = 1 + 1\/10 - 1\/2 = 1\/2 + 1\/10 = 3\/5 希望对你有帮助,新年快乐~...

|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+…+|1\/10-1\/9|=
解:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+…+|1\/10-1\/9| =(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+……+(1\/9-1\/10)=1\/2-(1\/3-1\/3)-(1\/4-1\/4)-……-(1\/9-1\/9)-1\/10 =1\/2-1\/10 =4\/10 =2\/5 祝你开心 ...

计算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10-1\/9|.
原式变成:-(1\/3-1\/2)-(1\/4-1\/3)-(1\/5-1\/4)-···-(1\/10-1\/9)前后项,如:-1\/3与-(-1\/3)就是1\/3可以约掉,-1\/4与-(-1\/4)就是1\/4可以约掉,那么最后剩下:原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10=4\/10=2\/5 这样解说希望楼主...

|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\\10-1\/9|=?各位大侠帮帮忙,作 ...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1/10-1\/9| 解:原式=﹙1/2﹚-﹙1/3﹚+﹙1/3﹚-﹙1/4﹚+﹙1/4﹚-………-﹙1/9﹚+﹙1/9﹚-﹙1/10﹚=﹙1/2﹚-﹙1/10﹚=0.4

|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/2005-1\/2004|=?
原式中,绝对值符号内都是负值,因此均应以其相反数为绝对值号外的值,即:原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/2004-1\/2005 =1\/2-1\/2005 =2004\/4010 =1002\/2005

|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10+1\/9|的答案与解析_百度知 ...
因为|1\/3-1\/2|=1\/2-1\/3 所以原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5...+1\/9-1\/10=1\/2-1\/10=2\/5

...|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10-1\/9|。
解:|1\/2-1|+|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|...|1\/10-1\/9| =(1-1\/2)+(1\/2-1\/3)+...+(1\/8-1\/9)+(1\/9-1\/10)=1-1\/2+1\/2-1\/3+...+1\/8-1\/9+1\/9-1\/10 =1-1\/10 =9\/10

...|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/2011-1\/2010|的值_百度知 ...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/2011-1\/2010| =|1\/2-1\/3|+|1\/3-1\/4|+|1\/4-1\/5|+...+|1\/2010-1\/2011| =1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+...+1\/2010-1\/2011 = 1\/2 - 1\/2011 =(2011-2)\/4022 =2009\/4022 ...

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