解：原式＝﹙1／2﹚－﹙1／3﹚＋﹙1／3﹚－﹙1／4﹚＋﹙1／4﹚－………－﹙1／9﹚＋﹙1／9﹚－﹙1／10﹚
＝﹙1／2﹚－﹙1／10﹚
＝0.4
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\\10-1\/9|=?各位大侠帮帮忙,作 ...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1／10-1\/9| 解：原式＝﹙1／2﹚－﹙1／3﹚＋﹙1／3﹚－﹙1／4﹚＋﹙1／4﹚－………－﹙1／9﹚＋﹙1／9﹚－﹙1／10﹚＝﹙1／2﹚－﹙1／10﹚＝0.4
计算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/100-1\/99|=
=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+...+1\/99-1\/100 =1\/2-1\/100 =49\/100
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+…+|1\/10-1\/9|=
解：|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+…+|1\/10-1\/9| =（1\/2-1\/3）+（1\/3-1\/4）+（1\/4-1\/5）+……+（1\/9-1\/10）=1\/2-（1\/3-1\/3）-（1\/4-1\/4）-……-（1\/9-1\/9）-1\/10 =1\/2-1\/10 =4\/10 =2\/5 祝你开心 ...
计算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10-1\/9|.
原式变成：-(1\/3-1\/2)-(1\/4-1\/3)-(1\/5-1\/4)-···-(1\/10-1\/9)前后项，如：-1\/3与-(-1\/3)就是1\/3可以约掉，-1\/4与-(-1\/4)就是1\/4可以约掉，那么最后剩下：原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10=4\/10=2\/5 这样解说希望楼主...
简便运算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/10-1\/9|
原式＝1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10 =2\/5
化简|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+……+|1\/10-1\/9|
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+……+|1\/10-1\/9|=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10=1\/2-1\/10=4\/10=2\/5
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|1\/...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|1\/9-1\/8|+1\/10-1\/9│ =1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7+1\/7-1\/8+1\/8-1\/9+1\/9-1\/10 =1\/2-1\/10 =2\/5 ...
求计算过程:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+……+|1\/100-1\/99|=?(要...
解：因为|1\/3-1\/2|=1\/2-1\/3, |1\/4-1\/3|=1\/3-1\/4, |1\/5-1\/4|=1\/4-1\/5……|1\/100-1\/99|=1\/199-1\/100 所以 原式=(1\/2-1\/3)+(1\/3-1\/4)+(1\/4-1\/5)+……+(1\/98-1\/99)+(1\/99-1\/100)=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/98-1\/99+1\/99-...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10+1\/9|的答案与解析
因为|1\/3-1\/2|=1\/2-1\/3 所以原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5...+1\/9-1\/10=1\/2-1\/10=2\/5
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|+|...
解：由题可知 1\/3-1\/2<0 1\/4-1\/3<0 1\/5-1\/4<0 ……1\/10-1\/9<0 所以原式=-（1\/3-1\/2）-（1\/4-1\/3）-（1\/5-1\/4）-……-（1\/10-1\/9）=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10 =2\/5 ...
