=1/2-1/10
=2/5
简便运算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/10-1\/9|
原式＝1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10 =2\/5
计算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/100-1\/99|=
=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+...+1\/99-1\/100 =1\/2-1\/100 =49\/100
计算:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10-1\/9|.
原式变成：-(1\/3-1\/2)-(1\/4-1\/3)-(1\/5-1\/4)-···-(1\/10-1\/9)前后项，如：-1\/3与-(-1\/3)就是1\/3可以约掉，-1\/4与-(-1\/4)就是1\/4可以约掉，那么最后剩下：原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10=4\/10=2\/5 这样解说希望楼主...
用简便方法计算|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\/2011-1\/2010|...
=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+...+1\/2010-1\/2011 = 1\/2 - 1\/2011 =(2011-2)\/4022 =2009\/4022
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1\\10-1\/9|=?各位大侠帮帮忙,作 ...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+...+|1／10-1\/9| 解：原式＝﹙1／2﹚－﹙1／3﹚＋﹙1／3﹚－﹙1／4﹚＋﹙1／4﹚－………－﹙1／9﹚＋﹙1／9﹚－﹙1／10﹚＝﹙1／2﹚－﹙1／10﹚＝0.4
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|1\/...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|1\/9-1\/8|+1\/10-1\/9│ =1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+1\/5-1\/6+1\/6-1\/7+1\/7-1\/8+1\/8-1\/9+1\/9-1\/10 =1\/2-1\/10 =2\/5 ...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+|1\/6-1\/5|+|1\/7-1\/6|+|1\/8-1\/7|+|...
解：由题可知 1\/3-1\/2<0 1\/4-1\/3<0 1\/5-1\/4<0 ……1\/10-1\/9<0 所以原式=-（1\/3-1\/2）-（1\/4-1\/3）-（1\/5-1\/4）-……-（1\/10-1\/9）=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/9-1\/10 =1\/2-1\/10 =2\/5 ...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/10+1\/9|的答案与解析
因为|1\/3-1\/2|=1\/2-1\/3 所以原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5...+1\/9-1\/10=1\/2-1\/10=2\/5
怎么解数字题:|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+…+|1\/100-1\/99|怎么解...
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+…+|1\/100-1\/99|=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+…+1\/99-1\/100=1\/2-1\/100=49\/100 由于中间相减项相消，所以算式化简为1\/2-1\/100
|1\/3-1\/2|+|1\/4-1\/3|+|1\/5-1\/4|+···+|1\/2005-1\/2004|=?
原式中，绝对值符号内都是负值，因此均应以其相反数为绝对值号外的值，即：原式=1\/2-1\/3+1\/3-1\/4+1\/4-1\/5+……+1\/2004-1\/2005 =1\/2-1\/2005 =2004\/4010 =1002\/2005
